Question

Two protons are 0.00500 m apart. Find the force between them.

Answer 1

Answer:

Force, $F=9.21\times 10^{-24}\ N$

Explanation:

Charge on proton is $+1.6\times 10^{-19}\ C$.

The electrical force between charges is given by the product of charges and divided by square of distance between them. So, electric force is :

$F=\dfrac{kq^2}{r^2}\\\\F=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.00500 )^2}\\\\F=9.21\times 10^{-24}\ N$

So, force between protons is $9.21\times 10^{-24}\ N$.