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Savatey [412]
4 years ago
10

Oscilloscope channel addition problem. Read the following oscilloscope settings carefully. Suppose you display a 1 kHz, 2 V sine

wave in channel A and a DC, 1V signal in channel B with sensitivities set on 1V/div. You select 'Add' so that the two signals are combined and you readjust the position so the trace is in the middle of the screen. If you switch the signal in channel B from DC to AC, what will happen? (Draw a picture if it helps.)
Physics
1 answer:
notsponge [240]4 years ago
3 0

Answer:

The signal will move down by 1 division

Explanation:

We have two signals here:

- An AC signal (sine wave), centered at 0 V, with amplitude 2 V (it means that it goes from a maximum of +2 V to a minimum of -2 V)

- A DC signal, which appears in the oscilloscope as a flat line, of 1 V

If we add these two signals together, we are adding a constant offset of +1 V to the sine wave, so the sine wave will move up by one division

Now, if we readjust the position so the trace is centered again at 0 V, we are moving the signal down by 1 division

Then, if we switch the signal in channel B from DC to AC, we are removing the constant offset of 1 V - so the signal will be now centered at -1 V. Therefore, the signal will move down by 1 division.

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Which best describes what is required for any sound wave to travel?
olganol [36]

Answer:

Any medium solid, liquid or gas is required for sound waves to travel.

Explanation:

A sound wave requires a medium to travel. Sound waves are mechanical waves that is why these waves require a medium to travel. Sound waves can travel through solids, liquids, and gases.

In solids, the particles of the medium are closely packed together as compared to liquids and gases. In liquids, particles are less tightly packed and almost negligible in gases.

Therefore sound waves produce vibration in the dense or solid medium. Denser the medium faster the sound waves travel. However sound waves can not travel through empty space.

8 0
4 years ago
Read 2 more answers
A force of attraction that exists between any two objects is _______. (1 point)
spayn [35]
The answer is Gravity

There's always a gravity between any 2 objects in this universe. between you and your computer, between you and the floor, between your chair and your table, etc.

We just dont feel it because we live in earth which negates all of those gravities with its own.
4 0
3 years ago
What is the magnetic force (in newtons) on a particle traveling in a 1.5 T magnetic field if q = 7.5 microcoulombs and v = 1.75
Alla [95]

Given:

B(Magnetic field): 1.5 T                                                                                

q=  7.5 microcoulombs                                                                                

v= 1.75 x 10 ∧6 m/s                                                                                    

The angle ∅ between B and v is 45 °.                                                    

Now we know that F= qvB sin ∅

Substituting these values we get:

F= 7.5 x 10∧-6 x 1.75 x 10∧6 x 1.5 x sin 45                                                

 F= 16.752 N



3 0
3 years ago
A lens of focal length 15.0 cm is held 10.0 cm from a page (the object ). Find the magnification .
nevsk [136]

Answer:

Magnification, m = 3

Explanation:

It is given that,

Focal length of the lens, f = 15 cm

Object distance, u = -10 cm

Lens formula :

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

v is image distance

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-10)}\\\\v=-30\ cm

Magnification,

m=\dfrac{v}{u}\\\\m=\dfrac{-30}{10}\\\\m=3

So, the magnification of the lens is 3.

3 0
3 years ago
The place you get your hair cut has two nearly parallel mirrors 6.5 m apart. As you sit in the chair, your head is 2.0 m from th
ASHA 777 [7]

Answer:

13 m

Explanation:

It is given that :

I got a haircut  sitting at a place having two parallel mirrors at a distance = 6.5 m apart

My head is at a distance of 2 m from the nearer mirror.

Now the light from the back of my head must go to (6.5 - 2) = 4.5 m to the back mirror.

Then it must go to 6.5 m to the front mirror and 2 m from the front mirror to my eyes.

So in order to see the back of my head, it will be = 6.5 + 2 + 4.5 = 13 m away.

4 0
3 years ago
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