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Komok [63]
3 years ago
11

A 500-kilogram sports car accelerates uni-

Physics
1 answer:
timama [110]3 years ago
3 0

Answer:

90 meters

Explanation:

Given:

x₀ = 0 m

v₀ = 0 m/s

v = 30 m/s

t = 6 s

Find:

x

x = x₀ + ½ (v + v₀)t

x = 0 + ½ (30 + 0)(6)

x = 90

The car travels 90 meters.

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A bowl of soup has_____? A:both PE and KE B:PE C:neither PE or KE D:KE
miskamm [114]

Answer:

A.

Explanation:

4 0
4 years ago
A wire is formed into a circle having a diameter of 19.0 cm and placed in a uniform magnetic field of 3.40 mT. The wire carries
nikklg [1K]

Answer:

Explanation:

Radius = 9.5 x 10⁻² m

area of circle = 3.14 x (9.5 x 10⁻² )²

A = 283.38 x 10⁻⁴ m²

magnetic moment = area x current

M = 283.38 x 10⁻⁴ x 5

= 1416.9 x 10⁻⁴  Am²

Torque = MBsinθ

M is magnetic moment , B is magnetic field .

Max torque = 1416.9 x 10⁻⁴  x 3.4 x 10⁻³ , for θ = 90

= 4817.46 x 10⁻⁷

= 481.7 x 10⁻⁶

= 481.7 μ J

Energy = - MBcosθ

Max  energy  when θ = 180

MB = 4817.46 x 10⁻⁷ J

Min energy = - 4817.46 x 10⁻⁷  for θ = 0

7 0
3 years ago
The difference in heights of the liquid in the two sides of the manometer is 43.4 cm when the atmospheric pressure is 755 mm hg.
Schach [20]

The atmospheric P is greater than the P in the flask, since the Hg level is lacking down lower on the side open to the atmosphere. 

43.4 cm x (10 mm / 1 cm) = 435 mm 

the density of Hg is 13.6 / 0.791 = 17.2 times better than the liquid in the manometer. This means that 1 mmHg = 17.2 mm of manometer liquid. 

435 mm manometer liquid x (1 mm Hg / 17.2 mm manometer liquid) = 25.3 mm Hg 

The pressure in the flask is 755 - 25.3 = 729.7 mmHg. 

729.7 mmHg x (1 atm / 760 mmHg ) = 0.960 atm.

4 0
3 years ago
While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the
Delvig [45]
8 km/h I think good luck if it's wrong
8 0
3 years ago
Read 2 more answers
What is the speed of a 50 g rock if its de broglie wavelength is 3.32x10^-34m?
ivann1987 [24]
We can find the momentum of the rock by using De Broglie's relationship:
p= \frac{h}{\lambda}
where
p is the momentum
h is the Planck constant
\lambda is the De Broglie's wavelength

By using \lambda=3.32 \cdot 10^{-34} m, we find
p= \frac{6.6 \cdot 10^{-34} Js}{3.32 \cdot 10^{-34} m}=1.99 kg m/s

The momentum of the rock is
p=mv
where m=50 g=0.05 kg is the mass and v is its velocity. Rearranging the equation, we find the speed of the rock:
v= \frac{p}{m}= \frac{1.99 kg m/s}{0.05 kg}=39.8 m/s
7 0
4 years ago
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