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Paraphin [41]
3 years ago
15

A bicycle wheel of radius 0.2 m can rotate freely about a fixed axis. A constant force of 3 N is applied tangentially to the whe

el for 0.4 s. The wheel starts to rotate from rest and its moment of inertia about the axis of rotation is 0.5 kg m². What is its angular velocity after 0.4 s?
Physics
1 answer:
GrogVix [38]3 years ago
3 0

Answer:

knowledge nothin' nothin' nothing nothin' nothin' mysterious mmysterious m

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We can compare these two interactions on the basis of impulse (see above), but sometimes, we are more interested in the forces (
kiruha [24]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 I =  476 \ N \cdot s

b

 I_1 =  14.21 \  N\cdot s

c

    F  = 20300 \  N

Explanation:

Considering the first question

From the question we are told that

   The force produced is F  =  3400 \ N

   The duration of the punch is  t =  0.14 \  s

Generally the impulse delivered is mathematically represented as

    I =  F  *  t

=>    I =  3400  *  0.14

=>    I =  476 \ N \cdot s

Considering the second  question

   The approaching velocity of the ball is  v_b  =  45 \ m/s

    The leaving  velocity of the ball is  v_l  =  -53 \ m/s

     The mass of the ball is  m_b  =  0.145 \  kg

Generally the magnitude of the impulse delivered is mathematically represented as

     I_1 =  m*  v_b  - m *  v_l

=>     I_1 =  [0.145 *  45]  - [0.145 * -53]

=>     I_1 =  14.21 \  N\cdot s

Considering the third  question

     The  duration of the impact of the bat is  t _1 =  0.7 \ ms  =  0.7 *10^{-3} \  s

      Generally the average force exerted by the bat is mathematically represented as  

       F  =  \frac{I_1}{t_1}

=>     F  =  \frac{14.21 }{0.7 *10^{-3}}

=>       F  = 20300 \  N

 

7 0
4 years ago
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