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Paraphin [41]
3 years ago
15

A bicycle wheel of radius 0.2 m can rotate freely about a fixed axis. A constant force of 3 N is applied tangentially to the whe

el for 0.4 s. The wheel starts to rotate from rest and its moment of inertia about the axis of rotation is 0.5 kg m². What is its angular velocity after 0.4 s?
Physics
1 answer:
GrogVix [38]3 years ago
3 0

Answer:

knowledge nothin' nothin' nothing nothin' nothin' mysterious mmysterious m

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What do the movements of stars and galaxies tell astronomers about how the universe formed?
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There's some Special Relativity in this lot, too.
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A 25 kg child is sitting at the top of a 4 m tall slide, what is his potential energy?
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Think about a girl on a swing. When is the kinetic energy of the girl zero?
Eduardwww [97]

Kinetic energy is energy of motion. Pick choice-A, at the top of the swing,  where she stops moving & then goes the other way.

7 0
3 years ago
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In a mass spectrometer a particle of mass m and charge q is accelerated through a potential difference V and allowed to enter a
Ghella [55]

Answer:

m = B²qR² / 2 V

Explanation:

If v be the velocity after acceleration under potential difference of V

kinetic energy  = loss of electric potential energy

1/2 m v² = Vq ,

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In magnetic field , charged particle comes in circular motion in which magnetic force provides centripetal force

magnetic force = centripetal force

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v = BqR / m

v² = B²q²R² / m²  ------------------------- (2)

from (1) and (2)

B²q²R² / m²  = 2 Vq / m

m = B²q²R² / 2 Vq

m = B²qR² / 2 V

7 0
3 years ago
Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 21.0 cm and carries a
Burka [1]

Solution :

a). B at the center :

     $=\frac{u\times I}{2R}$

Here, one of the current is in the clockwise direction and therefore, the other current must be in the clockwise direction in order to cancel out the effect of the magnetic field that is produced by the other.

Therefore, the answer is ANTICLOCKWISE or COUNTERCLOCKWISE

b). Also, the sum of the fields must be zero.

Therefore,

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So,

$\frac{I_1}{d_1}= \frac{I_2}{d_2}$

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$I_2=24.38 $ A

Therefore, the current in the outer wire is 24.38 ampere.

3 0
3 years ago
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