To solve this problem it is necessary to apply the equations related to the law of Maus.
By the law of Maus we know that

Where,
= Intesity of incident light
I = Intensity of polarized light
With our values we have that
6V/m

Then


Therefore the maximum value of the transmitted E vector is 3V/m
Answer: E = 7394.6N/C
Explanation:
Please find the attached file for the solution
Wavelength = (speed) divided by (frequency) = 10/0.5 = <span>20 </span>
Answer:
0.5 Amperes
Explanation:
Information that we have:
Power: 
Voltage: 
and we use the equation that relates this two quantities to the Current (I):

where I is the curent, P is the Power and V is the Voltage.
we substitute the values given for the Power and the Voltage to find the current:

the Current running into the bulb is 0.5 Amperes
I attached the requested diagram.
<em>In the case of the magnetic field in a bar</em> by convention, the direction of the field is taken out of the north pole and towards the south pole of the magnet. These types of images are commonly made of some ferrous material.
<em>In the case of the horseshoe </em>magnet, the highly concentrated magnetic field is distinguished between its legs. In the figure it is shown in a contribution from North to South, again by agreement, however outside the two poles, the magnetic field falls rapidly. A horseshoe magnet is basically a bent bar magnet.