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Daniel [21]
3 years ago
14

What are the real and complex solutions of the polynomial equation x^4+3x^2-4

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer: (D) -1,1,-2i,2i

Explanation:

x^4+3x^2-4 = 0\\x^2 \rightarrow z\\z^2 + 3z -4 = 0 \\z_1 = -4\\z_2 = 1\\x_{1,2} = \pm\sqrt{-4}=\pm 2 i\\x_{3,4} = \pm 1

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Given:
y = 2x + 6
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given sin A =3/-/34 and that angle S is in quadrant 1, find the exact value of tan A in simplest radical form using a ration
Vedmedyk [2.9K]

Answer:

\tan(A) = \frac{3}{5}

Step-by-step explanation:

Given

\sin(A) = \frac{3}{\sqrt {34}}

0 \le A \le 90 --- First Quadrant

Required

Find tan(A)

The sin of an angle is:

\tan(A) = \frac{Opposite}{Hypotenuse}

and

\sin(A) = \frac{3}{\sqrt {34}}

By comparison:

Opposite = 3

Hypotenuse = \sqrt{34

So, the Adjacent is:

Hypotenuse^2 = Adjacent^2 + Opposite^2

(\sqrt{34})^2 = Adjacent^2 + 3^2

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Collect like terms

Adjacent^2 =34 - 9

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Take square roots

Adjacent =\sqrt{25

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The tangent of an angle is:

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This gives:

\tan(A) = \frac{3}{5}

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