Answer:
➢ There are eight lone pairs of electrons in each of the three resonance structures of NO3- ion. These <u>eight lone pairs</u> are provides by three oxygen atoms. There are no lone pairs on nitrogen atom.
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<span>Following are important postulates of Kinetic theory of gases
1) Gases are made up of number of particles.
this particles behaves like hard and spherical objects, which are in constant state of motion.
2) The particles always travel in a straight line until they collide with another particle or the walls of the container.
3) Particles are of smaller size as compared to the distance between particles.
4) There exist minimal/no force of attraction between the gas particles neither there exist attractive interaction between the particles and the walls of the container.
5) Collisions between gas particles or with the walls of the container are elastic in nature.
Thus, statement a i.e. </span><span>Gas particles have a high force of attraction to one another or to the walls of the container contradicts the postulates of kinetic theory of gases</span>
Answer:
because strong heated makes temperatures and pressures reach the substance's triple point in its phase diagram, So the substance can be in a liquid case , and that is against the sublimation process meaning
which define as the transition of a matter or a substance from the solid phase to the gas phase directly, without passing through the intermediate liquid phase
sublimation process happens by absorbing of heat which makes molecules overcome attractive force between each other and changing to gas phase
but in the previous case it will pass through the liquid phase so it will not be sublimation process any more
Answer:as you add the base it added some PH. The Ph lever of white winegaer is2.4 - 3.4
Explanation:
Answer:
Concentration solution A was 0.5225 M
Explanation:
10.00 mL of solution A was diluted to 50.00 mL and yields 50.00 mL of solution B
According to laws of dilution- 
where, 
and 
are concentration of solution A and B respectively
and 
are volumes of solution A and B respectively
Here = 0.1045 M, = 50.00 mL and = 10.00 mL
Hence, 
So, concentration solution A was 0.5225 M
