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1 year ago

How many electrons must be lost in Li?.

Chemistry

1 answer:

luda_lava [24]1 year ago

7 0

One valence electron is lost by Lithium

<h3>What is Electron ?</h3>

Unattached or attached to an atom, an electron is a negatively charged subatomic particle. One of the three main types of particles within an atom is an electron that is bound to it. The other two are protons and neutrons.

Due to the fact that full valence shells are more stable states and that all noble gases have them, lithium wants to lose electrons in order to become like helium. Consequently, alkali metals lose one electron to achieve the closest noble gas configuration.

Each lithium atom loses an electron to become a Li+ cation when it forms chemical compounds with other elements. The anions in ionic compounds that are negatively charged are therefore attracted to these. There are many applications for lithium compounds.

Since full valence shells are more stable states, and all noble gases have them, lithium wants to lose electrons to become like helium. In order to obtain the nearest noble gas configuration, alkali metals must lose one electron.

Learn more about Electron here:

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Answer:

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3 years ago

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Which statements about the structure of the periodic table are true?

yuradex [85]

The correct statements about the structure of periodic table are:

1. The inner transition elements are placed at the bottom of the periodic table for easy viewing.

2. The distribution of electrons in energy levels is responsible for the shape of the periodic table.

Periodic table has more groups than periods.

And it has more metals than non metals.

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3 years ago

A precipitate forms when mixing solutions of sodium fluoride (NaF) and lead II nitrate (Pb(NO3)2). Complete and balance the net

Leya [2.2K]

Answer:

See explanation

Explanation:

The molecular equation shows all the compounds involved in the reaction.

The molecular equation is as follows;

2NaF(aq) + Pb(NO3)2(aq) -------> PbF2(s) + 2NaNO3(aq)

The complete ionic equation shows all the ions involved in the reaction

The complete ionic equation;

2Na^+(aq) + 2F^-(aq) + Pb^2+(aq) + 2NO3^-(aq) -------->PbF(s) + 2Na^+(aq) +2NO3^-(aq)

The net Ionic equation shows the ions that actually participated in the reaction

The net ionic equation is;

2F^-(aq) + Pb^2+(aq)--------> PbF(s)

3 0

3 years ago

Study the following reaction carefully. What classification should this reaction have? 4Al + 3O 2 2Al 2 O 3

nikitadnepr [17]

The reaction is a synthesis…

$4Al + 3O_2 \longrightarrow 2Al_2O_3\\$

… because two substances are combining to make one other substance.

$4\stackrel{\hbox{0}}{\hbox{Al}} + 3\stackrel{\hbox{0}}{\hbox{O}}_2 \longrightarrow 2\stackrel{\hbox{+3}}{\hbox{Al}}_2\stackrel{\hbox{-2}}{\hbox{O}}_3\\$

It is also a reduction-oxidation reaction because the oxidation number of Al increases from 0 to +3 and the oxidation number of O decreases from 0 to -2.

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3 years ago

A teacher gives a test to two algebra classes. The first class has 18 students, and the second has 24 students. If the average f

Morgarella [4.7K]

Answer:

The C) statement is true.

Explanation:

Let's call $x_1$ the average for the first class and $x_2$ the average for the second class. The overall average x is then:

$x=\frac{x_1*18+x_2*24}{18+24}\\x=\frac{84*18+x_2*24}{42}\\x=\frac{1512+x_2*24}{42}$

Since the average is given by $Average=\frac{Sum of all values}{Amount of values}$ . We can now calculate x assuming the maximun and minimun values of $x_2$ , 2400 (which is 100 times 24) and 0 respectivly. That gives:

$x=\frac{1512+2400}{42}\\x=93$

for it's maximun value and

$x=\frac{1512+0}{42}\\x=36$

for it's minimun value. So we get that x is between 36% and 93%.

5 0

3 years ago