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Tamiku [17]
1 year ago
9

How many electrons must be lost in Li?.

Chemistry
1 answer:
luda_lava [24]1 year ago
7 0

One valence electron is lost by Lithium

<h3>What is Electron ?</h3>

Unattached or attached to an atom, an electron is a negatively charged subatomic particle. One of the three main types of particles within an atom is an electron that is bound to it. The other two are protons and neutrons.

  • Due to the fact that full valence shells are more stable states and that all noble gases have them, lithium wants to lose electrons in order to become like helium. Consequently, alkali metals lose one electron to achieve the closest noble gas configuration.

  • Each lithium atom loses an electron to become a Li+ cation when it forms chemical compounds with other elements. The anions in ionic compounds that are negatively charged are therefore attracted to these. There are many applications for lithium compounds.

  • Since full valence shells are more stable states, and all noble gases have them, lithium wants to lose electrons to become like helium. In order to obtain the nearest noble gas configuration, alkali metals must lose one electron.

Learn more about Electron here:

brainly.com/question/860094

#SPJ4

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Calculate the mass of Na2O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reacti
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Answer:

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Explanation:

You know  the balanced reaction:

4 NA + O₂ ⟶ 2 Na₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:

  • Na: 4 moles
  • O₂: 1 mole
  • Na₂O: 2 moles

Being:

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  • O: 16 g/mole

the molar mass of the compounds participating in the reaction is:

  • Na: 23 g/mole
  • O₂: 2*16 g/mole= 32 g/mole
  • Na₂O: 2*23 g/mole +16 g/mole=  62 g/mole

Then by stoichiometry of the reaction they react and are produced:

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  • Na₂O: 2 moles* 62 g/mole= 124 g

Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?

massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}

mass of Na₂O=5.39 g

<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>

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