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Vika [28.1K]
3 years ago
14

The density of red wine is 1.01g/cm3 and the density of olive oil is 0.92g/cm3.A salad dressing that consisted of these two ingr

edients was left sitting too long.The ingredients separated in the bottle ,which ingredient is which layer?Explain.
Chemistry
1 answer:
Sauron [17]3 years ago
3 0

the red wine is the densest so, it will be on bottom olive oil will be on the top. because its less than the red wine

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For the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when
KATRIN_1 [288]

Answer: Concentration of N₂ is 4.8.10^{9} M.

Explanation: K_{c} is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For

N2(g) + 2 O2(g) ⇄ 2 NO2(g)

K_{c} = \frac{[NO2]^{2} }{[N2][O2]^{2} }

From the question concentration of NO2 is twice of O2:

[NO2] = 2[O2]

Substituting this into K_{c}:

K_{c} = \frac{[2O2]^{2} }{[N2][O2]^{2} }

8.3.10^{-10} = \frac{4O2^{2} }{[N2].O2^{2} }

[N2] = \frac{4O2^{2} }{8.3.10^{-10}.O2^{2}  }

[N2] = \frac{4}{8.3.10^{-10} }

[N2] = 4.8.10^{9}

The concentration of N2 in the equilibrium is [N2] = 4.8.10^{9}M.

6 0
3 years ago
Name every block in mc
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Answer:

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7 0
3 years ago
Read 2 more answers
How many moles are equal to 1.3 x 1024 atoms of aluminum?
marshall27 [118]

Answer:

<h3>The answer is 2.16 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

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From the question we have

n =  \frac{1.3 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 2.159468...

We have the final answer as

<h3>2.16 moles</h3>

Hope this helps you

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3 years ago
Fission and fusion reactions both release energy. However, only fusion reactions
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Answer:
<span>D) combine light nuclei
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Explanation:
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Many scientists have been involved in the development of the theory of the structure of
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Answer:

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