Answer: It may swell.
Explanation: Bacteria or mold will grow in it giving off gasses that are harmful to ingest. The swelling may cause the gas to burst or mold.
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here are the steps 2 get the same ans:
(NH4)2 CO3 has 2x N, 8x H, 1x C and 3x O per molecule
so its molecular mass = 2x14 + 8x1 + 1x12 + 3x16
=28+8+12+48
=96g
of that 96g, 8x1=8g is due to Hydrogen
so by ratio n proportion, 1.00g will have 1x8/96 = 1/12g = 0.083g of H
He Rydberg formula can be extended for use with any hydrogen-like chemical elements.
<span>1/ λ = R*Z^2 [ 1/n1^2 - 1/n2^2] </span>
<span>where </span>
<span>λ is the wavelength of the light emitted in vacuum; </span>
<span>R is the Rydberg constant for this element; R 1.09737x 10^7 m-1 </span>
<span>Z is the atomic number, for He, Z =2; </span>
<span>n1 and n2 are integers such that n1 < n2 </span>
<span>The energy of a He+ 1s orbital is the opposite to the energy needed to ionize the electron that is </span>
<span>taking it from n = 1 (1/n1^2 =1) to n2 = ∞ (1/n2^2 = 0) </span>
<span>.: 1/ λ = R*Z^2 = 1.09737x 10^7*(2)^2 </span>
<span>λ = 2.278*10^-8 m </span>
<span>E = h*c/λ </span>
<span>Planck constant h = 6.626x10^-34 J s </span>
<span>c = speed of light = 2.998 x 10^8 m s-1 </span>
<span>E = (6.626x10^-34*2.998 x 10^8)/(2.278*10^-8) = 8.72*10^-18 J ion-1 </span>
<span>Can convert this value to kJ mol-1: </span>
<span>(8.72*10^-18*6.022 x 10^23)/1*10^3 = 5251 kJ mol-1 </span>
<span>Lit value: RP’s secret book: 5240.4 kJ mol-1 (difference is due to a small change in R going from H to He+) </span>
<span>So energy of the 1s e- in He+ = -5251 kJ mol-1</span>
<h3>
Answer:</h3>
Concentration will be 0.1 M and not 0.050M
<h3>
Explanation:</h3>
This explains why the molarity is not 0.050 M but 0.1 M
Molarity is the concentration of a solution in moles per liter.
Therefore,
Molarity = moles ÷ Volume
In this case,
We have 1.34 g of CuCl₂ and a volume of 100 mL
To get the molarity we need to find the number of moles in 1.34 CuCl₂
Number of moles = Mass÷ molar mass
Molar mass of CuCl₂ = 134.45 g/mol
Therefore,
Moles of CuCl₂ = 1.34 g ÷ 134.45 g/mol
= 0.009965 moles
= 0.01 moles
Then we can calculate the molarity;
Molarity = Number of moles ÷ Volume
Volume of the solution is 100 mL or 0.1 L
Molarity = 0.01 moles ÷ 0.1 L
= 0.1 M
Therefore, the concentration of 1.34 g CuCl₂ in a volume of 100 mL is 0.1 M and not 0.050M.
Answer:
2, 4, 1, 3, 5
Explanation:
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