I did a few, to show you how.
Slide 1:
A) class A; range of 7
B) class a; 5.5
C) class b; 6.7 appx
D) class a
These are how to find each one:
Mean: add all the numbers and divide by the number of numbers. Ex. 1+2+3= 6/3=2
Median: middle of the numbers
Range: take the smallest value away from the largest value
IQR: find the median; find the range of the numbers above and below the median. Take the range of those two numbers that is the IQR
MAD: find the mean; take absolute value of numbers and subtract mean (|x|-mean); find sum of absolute value and difference; divide by the number of numbers.
I can help you if you want
Answer:
x = 65 , y = 64
Step-by-step explanation:
y - 16 and 2y + 4 are same- side interior angles and sum to 180° , that is
y - 16 + 2y + 4 = 180
3y - 12 = 180 ( add 12 to both sides )
3y = 192 ( divide both sides by 3 )
y = 64
then
2y + 4 = 2(64) + 4 = 128 + 4 = 132
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
2y + 4 is an exterior angle of the triangle , then
x + 67 = 132 ( subtract 67 from both sides )
x = 65
Answer:
(1/3)x + 3 >= 3
<=> (1/3)x >= 0
<=> x >= 0
=> The only value from set satisfies, that is 0.
Hope this helps!
:)