Question

A plane with an altitude of

Answer 1

The bomb takes 55.33 seconds to reach its target on the ground

Step-by-step explanation:

The formula of the height of a free fall object is

h = ut + $\frac{1}{2}$ g t², where

1. h is the vertical distance

2. u is the initial speed of the object

3. t is the time of the object's trip

4. g is the acceleration of gravity

A plane with an altitude of  15000 meters drops a  bomb

We need to find how long it takes to reach its target on the ground

∵ The altitude of the plane is 15000 meters

∴ h = 15000 m

∵ The bomb is dropped ⇒ initial velocity is 0

∴ u = 0 m/s

∵ g = 9.8 m/s²

- Substitute these values in the formula above

∴ 15000 = (0)t + $\frac{1}{2}$ (9.8) t²

∴ 15000 = 4.9 t²

- Divide both sides by 4.9

∴ t² = 3061.22

- Take √ for both sides

∴ t = 55.33 seconds

The bomb takes 55.33 seconds to reach its target on the ground

Learn more

You can learn more about the rules of projectile motion in brainly.com/question/6902645

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