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3 years ago

If θ is an angle in standard position and its terminal side passes through the point (-4,-5), find the exact value of

Mathematics

1 answer:

NARA [144]3 years ago

7 0

9514 1404 393

Answer:

cot(θ) = 4/5

Step-by-step explanation:

In the polar/rectangular coordinate representation (x, y) ⇔ (r; θ), we know that ...

(x, y) = (r·cos(θ), r·sin(θ))

From the various trig definitions and identities, we also know that ...

cot(θ) = cos(θ)/sin(θ) = (x/r)/(y/r) = x/y

For the given (x, y) = (-4, -5), the cotangent is ...

cot(θ) = -4/-5 = 4/5

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PLEASE HELP ME

sineoko [7]

Answer:

C. Exponential

Step-by-step explanation:

If the function is linear, the differences will be equal.

d₁ = y₁ − y₀ = 4.2 − 0.6 = 3.6

d₂ = y₂ − y₁ = 29.4 − 4.2 = 25.2

d₃ = y₃ − y₂ = 205.8 − 29.4 = 176.4

d₄ = y₄ − y₃ = 1440.6 − 205.8 = 1234.8

The differences are not equal, so this is not linear.

If the function is quadratic, the differences of the differences will be equal.

d₂ − d₁ = 25.2 − 3.6 = 21.6

d₃ − d₂ = 176.4 − 25.2 = 151.2

d₄ − d₃ = 1234.8 − 176.4 = 1058.4

The differences of the differences are not equal, so this is not quadratic.

If the function is exponential, the ratios will be equal.

r₁ = y₁ / y₀ = 4.2 / 0.6 = 7

r₂ = y₂ / y₁ = 29.4 / 4.2 = 7

r₃ = y₃ / y₂ = 205.8 / 29.4 = 7

r₄ = y₄ / y₃ = 1440.6 / 205.8 = 7

The ratios are equal, so the function is exponential.

5 0

3 years ago

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

Part a: The height of the ball when t = 2 seconds:

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

Part b: The height of the ball when t = 4 seconds:

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$