The set of all even numbers less that fourteen would include 2,4,6,8,10,and 12.
The Cartesian product of two sets can be defined as the following: the set of all possible pairs where the 1st coordinate is an element of the 1st set and the 2nd coordinate is the element of the 2nd set. This has an obvious generalization for n sets (the cartesian product has then n coordinates).
Let us pick now all the pairs that have 100 as their first coordinate. We then have 2 choices for the 2nd coordinate, 1 and 2. Hence, the 2 pairs are: (100,1), (100,2). Similarly, if 200 is the first coordinate, the pairs are (200,1), (200,2).
These 4 pairs are the cartesian product (we have 4 pairs =2 elements from X* 2 elements from Y) .
It helps to remember that the cartesian product has as many elements as the product of the number of elements of each set.
The given question is
Multiplying and divide by 2
Again multiplying and dividing by 2
And
So we will get
Correct option is D
Answer:
The value after 0 years = $ 800
The value after 1 year = $600
The value after 2 years = $450
The value after 3 years = $337.5
The value after n years = computer cost at (n-1) year -
Step-by-step explanation:
- he cost of computer = $ 800
- It losed 1/4th of value every year.
- The value of computer after 0 years = cost of computer = $ 800
- The value after 1 year = 800 - ( ) = $600
- The value after 2 years = 600 - ( ) = $450
- The value after 3 years = 450 - ( ) = $337.5
- The value after n years = computer cost at (n-1) year -
Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.
Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs
Solve for n
4n/9-n(1/5+1/4) = -3
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540
Total number of products bought
= n+n = 540+540 = 1080
