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3 years ago

Which number is a prime number 14,13,21,33 ?

2 answers:

5 0

The answer you are looking for would be B. 13.

Prime numbers are numbers that are not divisible by any numbers except 1 and itself. All even numbers (except 2) are divisible by 2, therefore eliminating 14.
21 and 33 are both divisible by 3 (21/3 = 7 and 33/3 = 11). Thus making 13 the prime number.

I hope this helps!

Levart [38]3 years ago

3 0

A prime number means that the number is only divisible by one and itself.

14 is a multiple of 2 and 7, so 14 wouldn't be it.

21 is a multiple of 3 and 7, so 21 wouldn't be it.

33 is a multiple of 3 and 11, so 33 wouldn't be it.

13 is only divisible by itself because no number can be multiplied to get 13.

So the correct answer is : 13 is the prime number.

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According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t

nalin [4]

Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that $p = 0.2$

Suppose that sixteen adults in the United States are selected randomly.

This means that $n = 16$

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281$

$P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126$

$P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111$

$P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981$

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

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3 years ago

Answer these 3 questions ASAP pls..

matrenka [14]

That’s the answers hope this helps.

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3 years ago

Given b(x) = X+41, what is b(-10)?

spin [16.1K]

Answer:

b(10) = 31

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A black line is longer than a gray line. The gray line is longer than a white line. Is the black line shorter or longer than the

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The gray line is longer than the white line.
The black line is longer than the gray line.

White    -------------------------

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Answer: The black line is longer than the white line.

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