The answer to the first one is m<1 = 97°
m<2 = 88°
m<3= 45°
m<4 = 114°
m<5 = 97°
m<6 = 88°
m<7= 114°
m<8=45°
m<10=88°
m<11= 45°
m<13= 88°
m<14= 97°
m<15=97°
m<16= 88°
the line-of-sight distance from the television camera to the base of the stadium is 1449.28 m .
<u>Step-by-step explanation:</u>
A blimp provides aerial television views of a baseball game. The television camera sights the stadium at a 12° angle of depression. The altitude of the blimp is 300 m. We need to find What is the line-of-sight distance from the television camera to the base of the stadium . Let's find out:
According to question , given scenario is in a right angle triangle where
, where x is angle of depression.
We know that 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the line-of-sight distance from the television camera to the base of the stadium is 1449.28 m .
Answer:
-99.9
Step-by-step explanation:
Angle 2 and 5 are alternate interior angle and they are congruent. That means that m <5= 35°.
Answer:0.50
Step-by-step explanation:
just did it