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barxatty [35]
3 years ago
14

Which quadrilateral has two pairs of different but equal adjacent sides?

Mathematics
2 answers:
Igoryamba3 years ago
7 0
A kite has two pairs of congruent adjacent sides. More specifically, if we have a four sided figure with sides p, q, r, s (as shown in the diagram), then 

p = q
r = s

Furthermore, p is not equal to r or s. Similarly, q is not equal to r or s. All of these facts are visually shown by the tick-marks. Segments with a single tick-mark indicate they are same length. Segments with a double tick-mark are the same length. 

dem82 [27]3 years ago
4 0
The answer is most likely a 'kite'. If not it would be something very similar.
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since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

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\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

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