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baherus [9]
3 years ago
15

72=8×9 times as many

Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0

Answer:

9x8=72

Step-by-step explanation:

Your welcome

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A. Using geometry terms, identify what the side road would be called?
Fofino [41]

The vertical angles from the attached image will be; 1 and 4; 2 and 3; 5 and 8; 6 and 7.

The Linear pair angles would be: 1 and 3; 2 and 4; 5 and 7; 6 and 8; 1 and 2; 3 and 4; 5 and 6; 7 and 8

<h3>How to identify angle theorems?</h3>

A) From the attached image, the side roads resemble 2 parallel lines cut by a transversal.

Now, if we consider the roads to be very fat lines, then it means that the main road is the transversal while the two side roads are parallel to each other.

B) Vertical angles are defined as angles that are opposite of each other The vertical angles from the attached image will be; 1 and 4; 2 and 3; 5 and 8; 6 and 7.

The Linear pair angles would be: 1 and 3; 2 and 4; 5 and 7; 6 and 8; 1 and 2; 3 and 4; 5 and 6; 7 and 8when two lines cross

The supplementary angles would be: 3 and 5; 4 and 6

C) If a fourth road is constructed, it will be perpendicular to the main road, or perpendicular to the two side roads, and it will form a right triangle.

Thus, the acute angles of the triangles will be complementary because their sum will be 90°

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5 0
2 years ago
X+2÷4-5x-2÷12=8-2x÷5
Delicious77 [7]
The answer to your problem is X= -155/54
4 0
3 years ago
Something divided by 6 = 7 8 3
Karo-lina-s [1.5K]
The answer is going to be 4698
7 0
3 years ago
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based on past games, the probablity that a basketball player will make his next free throw is 5/12. what is the probablity that
Svetradugi [14.3K]

Answer:

The probability would be 7/12

Step-by-step explanation:

Since making or missing a shot is a binary situation, we know that we can subtract the probability from 1 and get the opposite.

1 - 5/12 = 7/12

8 0
3 years ago
Find the equation of the line shown<br><br> pls help
pochemuha

Answer:

y= 1/2x+ 0

or:

y= 1/2x+ 0

Step-by-step explanation:

4 0
3 years ago
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