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kirill115 [55]
3 years ago
8

A retired math teacher takes his shopping. he tells nephew that they can spend x dollars and 14x=931 . What operation does the n

ephew need to use to find how much money they can​ spend?
Mathematics
1 answer:
navik [9.2K]3 years ago
8 0
The nephew would need to use division to isolate x giving him $66.50 to spend
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1. Jordan's washing machine is broken. Since her machine is pretty old, she doesn't want to spend more than $100
ahrayia [7]

Answer:

I think it would be D

Step-by-step explanation:

20 x 3 =  60      60+35= 95          20/4 = 5  

4 0
3 years ago
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The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
A moving company charges $40 plus $0.25 per mile to rent a van. Another company charges $25 plus $0.35 per mile to rent the same
Bond [772]
<h3>Answer:</h3>

c. 150 miles

<h3>Step-by-step explanation:</h3>

You want to find the number of miles (m) that make the charges equal.

... 40 +0.25m = 25 + 0.35m

... 15 = 0.10 m . . . . . . add -25-0.25m

... 150 = m . . . . . . . . . divide by the coefficient of m

For 150 miles, the rental cost will be the same for both companies.

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The side of the square is (12x+52)/4=3x+13.
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Ir is a repeated number
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