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3 years ago

8

A retired math teacher takes his shopping. he tells nephew that they can spend x dollars and 14x=931 . What operation does the n

ephew need to use to find how much money they can spend?

1 answer:

navik [9.2K]3 years ago

8 0

The nephew would need to use division to isolate x giving him $66.50 to spend

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A cone has a volume of 1,256 cubic centimeters. If the height of the cone is 12 centimeters, what is the radius of the base in c

luda_lava [24]

Answer:

The radius 10 cm

Step-by-step explanation:

∵ The volume of the cone = 1/3 πr²h

∵ v = 1256 cm³

∵ h = 12 cm

∴ 1256 = 1/3 π (12) r²

∴ r² = 1256 × 3/12π = 100 cm

∴ r = √100 = 10 cm

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3 years ago

Solve 37+z≤54. Graph the solution.

iragen [17]

Answer:

z ≤ 17

Step-by-step explanation:

Step 1: Subtract 37 from both sides.

$37 + z - 37\leq 54-37$
$z\leq 17$

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3 years ago

Read 2 more answers

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

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3 years ago

Whats the product of (3-2i) and (7+6i)?

Alona [7]

Answer: the product is = 33+4i

Step-by-step explanation:

21+4i-12i^2

21+4i-12(-1) i^2=-1

21+4i+12

your answer would be 33+4i .

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3 years ago

What is the expression 3(x+6)+21+14x in simplest combined form

kolezko [41]

Answer:

Step-by-step explanation:

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