Answer:
68
Step-by-step explanation:
We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.
We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.
This can be expressed as;
P(170<X<180)
This can be evaluated in Stat-Crunch using the following steps;
In stat crunch, click Stat then Calculators and select Normal
In the pop-up window that appears click Between
Input the value of the mean as 175 and that of the standard deviation as 5
Then input the values 170 and 180
click compute
Stat-Crunch returns a probability of approximately 68%
V=2 BECAUSE
7v2+1=29
7v2=28
v2=4
v=2
I'm assuming it is asking for surface area.
SA = 2(lw) + 2(hw) + 2(lh)
SA = 2(3*4) + 2(4*8) + 2(3*8)
SA = 2(12) + 2(32) + 2(24)
SA = 24 + 64 + 48
SA = 136 square feet
B. 60°
This is an equilateral triangle, so all angles should be equal. 180/3=60, so you’re answer is 60.
Answer: 30
Step-by-step explanation:
Just did it