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3 years ago

Someone please help !!

Mathematics

2 answers:

EastWind [94]3 years ago

6 0

Answer:

It is C.

Explanation:

If you take a closer look at the data, the lower extreme is 10, and which one shows 10 as the lower extreme? It is option C.

larisa86 [58]3 years ago

5 0

The answer is option c

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Determine which of the following pairs of fractions are equivalent.

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You only wrote one option, but luckily, those two fractions ARE equivalent!

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What is the answer to 64+(-15)

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Can you pls help <br> 5+4-(8*3-22)^4*4<br> pls help you get 25 points

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Answer:

5 + 4 - (8 * 3 - 22)⁴ * 4 = -55

Step-by-step explanation:

5 + 4 - (8 * 3 - 22)⁴ * 4

Follow PEMDAS which states you need to do equations in the order of:

Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction.

Knowing this, simplify inside the parenthesis by multiplying 8 and 3 first.

5 + 4 - (24 - 22)⁴ * 4

Now subtract 22 from 24 inside the parenthesis.

5 + 4 - (2)⁴ * 4

Since we are done with parenthesis, move on to the next part of PEMDAS which says to do exponents next. Take 2 to the power of 4.

5 + 4 - 16 * 4

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Now that we are done with multiplication/division, move on to the last part of PEMDAS which says to add/subtract. Add 5 and 4.

9 - 64

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3 years ago

Suppose you want to decrease your margin of error by a factor of 3. by what factor, do you need to increase your sample size? in

elena55 [62]

The sample size, n required to produce a margin of error, M, in a probability proportion distribution is given by:

$n= \frac{p(1-p)z_{\alpha/2}^2}{M^2}$

The above formular shows that the sample size is inversely proportional to the Margin of error.

Then we have:

$n= \frac{k}{M^2}$

where k is some constant.

Now suppose we decrease M by a factor of 3,

$\left(i.e.\ \frac{M_1}{M_2} =3\right)$

$n_1= \frac{k}{M_1^2} \\ \\ n_2= \frac{k}{M_2^2} \\ \\ \frac{n_2}{n_1} = \frac{k}{M_2^2} / \frac{k}{M_1^2} = \frac{k}{M_2^2} \times \frac{M_1^2}{k} = \frac{M_1^2}{M^2_2} =\left( \frac{M_1}{M_2} \right)^2=3^2=9 \\ \\ n_2=9n_1$

Therefore, if we decrease the Margin of error by a factor of 3, we need to increase the sample size by a factor of 9.

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4 years ago