If m<IEF =71°, then what is m<AED?

Does anybody know the answer to this

vekshin1

Answer: I believe it's b

Step-by-step explanation:

\pi = 3.14159265...

It is most likely b

4 0

3 years ago

Read 2 more answers

Bob spent $78,475 on supplies to build a house. The house is 2,150 square

solong [7]

Im pretty sure it’s $36.50 because you divide 78,475 by 2,150

5 0

3 years ago

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Joyce is comparing two different internet providers to see which is a better deal. The cost of service from Provider S can be re

maxonik [38]

This means an initial fee of $45 have to be paid to the provider and a charge of $35 per month.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

Where y, x are variables, m is the rate of change and b is the initial value of y.

Let S represent the total cost of service for x months. Given:

y = 35x + 45

This means an initial fee of $45 have to be paid to the provider and a charge of $35 per month.

Find out more on Linear equation at: brainly.com/question/13763238

5 0

2 years ago

Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

2 years ago

Find the area of each parallelogram plz help

xxTIMURxx [149]

Answer: The area of the parallelogram is:
_______________________________________________________
$\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
b = 50.5 in.

h = 23.25 in.
____________________________________________________________
Method 1) A = b * h =

= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>____________________________________________________________
Method 2) A = b * h =

= (50 ½ in) * (23 <span>¼ in) =

= (</span> $\frac{101}{2}$ in) * ( $\frac{93}{4}$ <span> in) ;
</span>___________________________________________________________
Note: "50 ½ " = [(50*2) + 1 ] / 2 = $\frac{101}{2}$ ;

Note: "23 ¼ " = [(23*4) + 1 ] / 4 = $\frac{93}{4}$ ;
____________________________________________________________
→ A = ( $\frac{101}{2}$ in) * ( $\frac{93}{4}$ in) ;

→ A = $\frac{(101*93)}{(2*4)}$ in² = $\frac{9393}{8}$ in² ;

→ A = (9393/8) in² =

→ A = $\frac{9393}{8}$ in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________

5 0

3 years ago

If m<IEF =71°, then what is m<AED?​

If m<IEF =71°, then what is m<AED?