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2 years ago

Please I need help with this

Mathematics

2 answers:

rodikova [14]2 years ago

8 0

Can you take a closer pic of this

Anna007 [38]2 years ago

5 0

Yes it is a function because if you do the straight verticals line test, a straight line will only hit one point no matter where it's drawn. 2) is max is the highest point and min is lowest point it reaches 3) domain is with the X axis and how long it goes Range is the Y axis on how long it goes. Hope this helps!

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6• 2hen+3pens-5anchors

choli [55]

Answer:

$180$

Step-by-step explanation:

$6 \times 2 \times 3 \times 5$

$12 \times 15$

$=180$

7 0

3 years ago

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The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed

algol [13]

Answer:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

$p_v = P(\chi^2_{5} >5.860)=0.32$

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number: 1, 2 , 3 , 4 , 5 ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are given:

$O_{1}=27$ $O_{2}=31$

$O_{3}=42$ $O_{4}=40$

$O_{5}=28$ $O_{6}=32$

The expected values are given by:

$E_{1} =\frac{1}{6}*200=33.33$ $E_{2} =\frac{1}{6}*200=33.33$

$E_{3} =\frac{1}{6}*200=33.33$ $E_{4} =\frac{1}{6}*200=33.33$

$E_{5} =\frac{1}{6}*200=33.33$ $E_{6} =\frac{1}{6}*200=33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

Now we can calculate the degrees of freedom for the statistic given by:

$df=Categories-1=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >5.860)=0.32$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

4 0

3 years ago

What is the simplest form of 6/27?

aivan3 [116]

The fraction 6/27 is equivalent1 to 2/9.

This is a proper fraction once the absolute value of the top number or numerator (6) is smaller than the absolute value of the bottom number or denomintor (27).

8 0

3 years ago

What is the area of a rectangle with length (3^2)^2 meters and width of 3^2 meters?

Luda [366]

Answer:

729m^2

Step-by-step explanation:

Area of rectangle = length x width

From the question, we know that length = 3^2^2 = 81 ( three squared is 9. Nine squared is 81)

width = 3^2 = 9.

Now for the area: length x width = 81 x 9 = 729m^2.

Please mark brainiest.

4 0

2 years ago

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Chris walks up to a tank of water that can hold up to 25 gallons When it is active, a

nignag [31]

Answer:

Step-by-step explanation:

3 0

3 years ago

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