The answer is g) y= 27.6 and x=11
1.5y=41.4
1.5y/1.5=41.4/1.5
y=27.6
Α = 1- (95/100) = 1-0.95 = 0.05
p = 1- α/2 = 1- 0.05/2 = 1-0.025 = 0.975
Degrees of freedom, df = Sample size -1 = 11-1 = 10
From t-tables, with cumulative probability pf 0.975 and df of 10,
Critical value = 2.228
Answer:
x = 2.5 or -0.8
Step-by-step explanation:
Here, we are to use completing the square method to solve for the values of x
Firstly, we divide through by 4
= x^2 -7/4x -2 = 0
Now, we move the two term to the right hand side
x^2 -7/4x = 2
Now, we divide the coefficient of x by 2 and square it;
That would be;
(-7/4 * 1/2)^2 = 49/64
we now add this value to both sides of the equation
x^2 -7/4x + 49/64 = 2 + 49/64
The right hand side can be rewritten as;
(x-7/8)^2 = 177/64
taking the square root of both sides
x-7/8 = √(177/64)
x = 7/8 ± √(177/64)
x = 7/8 + √(177/74) or 7/8 - √(177/64)
= x = 2.53802 or -0.788017
Which to the nearest tenth is
x = 2.5 or -0.8