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3 years ago

What number is 30% of 20?(will give Brainliest)

1 answer:

6 0

In order to get the answer you will have to divide 30 by 100 then divide the number you get from that by 20 to receive your answer.

20/x=100/30

(20/x)*x=(100/30)*x

20=3.33333333333*x

(3.33333333333) to get x

20/3.33333333333=6

Therefore your answer is "6."

Hope this helps

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Given g(x) = 10x + 2, find x when g(x) = 2.

Elan Coil [88]

Answer:

x=0

Step-by-step explanation:

We are given:

g(x) =10x +2

and

g(x)=2

g(x) is equal to both 10x+2 and 2. Therefore, by substitution, we can set them equal to each other

10x+2=2

Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides

10x+2-2=2-2

10x=0

To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.

10x/10=0/10

x=0

8 0

3 years ago

H^-16/h^x=1/h^24 can someone help me please

Basile [38]

Given:

Consider the equation is

$\dfrac{h^{16}}{h^x}=\dfrac{1}{h^{24}}$

To find:

The value of x.

Solution:

We have,

$\dfrac{h^{-16}}{h^x}=\dfrac{1}{h^{24}}$

Using properties of exponents, we get

$h^{-16-x}=h^{-24}$ $[\because \dfrac{a^m}{a^n}=a^{m-n},a^{-n}=\dfrac{1}{a^n}]$

On comparing both sides, we get

$-16-x=-24$

Add 16 on both sides.

$-x=-24+16$

$-x=-8$

Multiply both sides by -1.

$x=8$

Therefore, the value of x is 8.

5 0

3 years ago

Yeah can someone help me plz

erastovalidia [21]

11. you do 3x3=9 then plus 9+2 = 12 then 12 x 12 = 144
sorry idk 10.

3 0

3 years ago

Tabitha collects quarters from different states. The value of her collection is $17.75. How many quarters does she have in her c

kvasek [131]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago