Answer:
Given equation of parabola is
and
2
=64x ......(i)
The point at which the tangent to the curve is parallel to the line is the nearest point on the curve.
On differentiating both sides of equation (i), we get
2 y
dx
d y
=64
⇒
dx
d y
=
and
32
Also, slope of the given line is −
3
4
∴−
3
4
=
and
32
⇒and=−24
From equation (i), (−24)
2
=64x⇒x=9
∴ the required point is (9,−24)
Explanation:
This is the correct answer you want
please follow the
To solve this we use the equation,
M1V1 = M2V2
where M1 is the concentration of the stock
solution, V1 is the volume of the stock solution, M2 is the concentration of
the new solution and V2 is its volume.
65 x V1 = 2 x 200 L
V1 = 6.15 L
Explanation:
Element X forms a chloride with the formula XCl 2 , which is a solid with a high melting point. X would most likely be in the same group of the Periodic Table as. (a) Na (b) Mg (c) Al (d) Si. the answer is Mg .
3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)
This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.
Hope this helped!
"CH3COOH + H2O CH3COO- + H3O+" is the equation among the choices given in the question <span>represents the reaction of acetic (ethanoic) acid with water. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.</span>
