All categories

3 years ago

How do we determine the number of electrons in a neutral atom?

Chemistry

1 answer:

Elodia [21]3 years ago

3 0

this is the answer of your question .

Hope it helped you

You might be interested in

How many grams of KCIO3 are needed to produce 5.00 of O2 at STP?

Arlecino [84]

2KClO₃ → 2KCl + 3O₂

mole ratio of KClO₃ to O₂ is 2 : 3

∴ if moles of O₂ = 5 mol

then moles of KClO₃ = $\frac{5 mol * 2}{3}$

= 3.33 mol

Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃

= 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol

= 407.93 g

6 0

3 years ago

How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?

dusya [7]

Answer:

1.3 moles/ 1.33150727 moles

Explanation:

350g x 1 mol/262.86g = 1.3 moles

6 0

3 years ago

Read 2 more answers

BRAINLIESTTT ASAP! PLEASE HELP ME :)

gogolik [260]

Answer:

"Heat of combustion"

Explanation:

A physical property is characteristic of a substance that can be observed or measured without changing its chemical composition, such as color, molecular weight, and volume. A chemical property can only be observed or measured by changing the chemical composition of the substance, such as reactivity, flammability and oxidation states.

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

A sample of nitrogen gas occupies a volume of 2.55 L when it is at 755 mm Hg and 23 degrees Celsius. Use this information to det

ivolga24 [154]

Answer: The number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

Explanation:

To calculate the amount of nitrogen gas, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 755 mmHg

V = Volume of the gas = 2.55 L

T = Temperature of the gas = $23^oC=[23+273]K=296K$

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

$755mmHg\times 2.55L=n\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 296K\\\\n=\frac{755\times 2.55}{62.364\times 296}=0.1043mol$

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=755mmHg\\V_1=2.55mL\\T_1=23^oC=[23+273]K=296K\\P_2=?\\V_2=4.10L\\T_2=18^oC=[18+273]K=291K$

Putting values in above equation, we get:

$\frac{755mmHg\times 2.55L}{296K}=\frac{P_2\times 4.10L}{291K}\\\\P_2=\frac{755\times 2.55\times 291}{4.10\times 296}=461.6mmHg$

Hence, the number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

6 0

3 years ago

Read 2 more answers

In the process of oxidizing i− to i2, so42− is reduced to so2. how many moles of so2 are produced in the formation of one mole o

mafiozo [28]

The balance chemical equation is follow,

2 I⁻ + SO₄²⁻ + 4 H⁺ → I₂ + SO₂ + 2 H₂O

According to this reaction, 2 moles of I⁻ reacts with 1 mole of SO₄²⁻ to produce 1 mole of I₂ and 1 mole of SO₂.

Result:
So with the formation of 1 mole of I₂, 1 mole of SO₂ is produced.

5 0

3 years ago