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BARSIC [14]
3 years ago
14

What reaction would the chemical equation 2H2O →2H2 + O2 represent?

Chemistry
2 answers:
Alex777 [14]3 years ago
7 0
This is a decomposition reaction because the compound of water is being broken up into 4 hydrogen molecules and 2 Oxygen molecules. Hope this helps!
ASHA 777 [7]3 years ago
6 0

Answer:

The correct answer is water electrolysis.

Explanation:

Water electrolysis is the decomposition of water (H2O) into the gas oxygen (O2) and hydrogen (H2) using a continuous electric current, supplied by a power source, which can be a battery or a battery, which is connected by electrodes to water. This reaction is endothermic, and the products of the reaction are hydrogen and oxygen in a gaseous state.

Have a nice day!

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Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
garri49 [273]

Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

                                = \frac{5.25}{9.85}

                                = 0.527  

Calculate the dew point as follows.

                     y_{1} = 0.5,      y_{2} = 0.5  

          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

           \frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}

             \frac{1}{P} = 0.101966 bar^{-1}              

                             P = 9.807

Composition of the liquid phase is x_{i} and its formula is as follows.

                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{9.2}

                               = 0.5329

                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
3 years ago
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
Name of compound AgC2H3O2
BaLLatris [955]

Answer:

AgC2H3O2 is: Silver acetate

7 0
3 years ago
A rapidly falling object at a high altitude has _____
alisha [4.7K]
A. high potential energy and zero kinetic energy.
7 0
4 years ago
A cube has a length of 1.02 cm and a mass of .001012 kg what is its density ​
slega [8]

Answer:

d = 9.5× 10⁻⁴ Kg/cm³

Explanation:

Given data:

Length of cube = 1.02 cm

Mass of cube = 0.001012 Kg

Density of cube = ?

Solution:

The length , height and width of cube is always same. Thus the volume of cube is,

Volume = length × height× width

Volume = 1.02 cm × 1.02 cm × 1.02 cm

Volume = 1.06 cm³

Density of cube:

d = 0.001012 Kg /1.06 cm³

d = 9.5× 10⁻⁴ Kg/cm³

8 0
3 years ago
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