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BARSIC [14]
3 years ago
14

What reaction would the chemical equation 2H2O →2H2 + O2 represent?

Chemistry
2 answers:
Alex777 [14]3 years ago
7 0
This is a decomposition reaction because the compound of water is being broken up into 4 hydrogen molecules and 2 Oxygen molecules. Hope this helps!
ASHA 777 [7]3 years ago
6 0

Answer:

The correct answer is water electrolysis.

Explanation:

Water electrolysis is the decomposition of water (H2O) into the gas oxygen (O2) and hydrogen (H2) using a continuous electric current, supplied by a power source, which can be a battery or a battery, which is connected by electrodes to water. This reaction is endothermic, and the products of the reaction are hydrogen and oxygen in a gaseous state.

Have a nice day!

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Answer: Fluorine.

Explanation:

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Which type of reactions form salts?
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Answer:

Neutralization reactions

Explanation:

A neutralization reaction is a reaction between an acid and a base. Products of this type of reaction is water and a salt. The pH of the salt product would depend on how strong or weak the base and acid would be when they react with each other. Although the characteristics of bases and acids are practically polar opposites, when combined, they cancel each other our producing a neutralized product.

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Consider the cell described below at 259 K: Ni | Ni2+ (1.15 M) || Fe3+ (2.23 M) | Fe Given the standard reduction potentials fou
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3 years ago
Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following
bearhunter [10]

Answer:

210.7~g~MgCO_3

Explanation:

We have to start with the <u>reaction</u>:

MgCO_3~->~MgO~+~CO_2

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:

(12*1)+(16*2)=44~g/mol

In other words: 1~mol~CO_2=~44~g~CO_2. With this in mind, we can calculate the moles:

110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2

Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:

2.5~mol~CO_2=2.5~mol~MgCO_3

With the molar mass of MgCO_3 ((23.3*1)+(12*1)+(16*3)=84.3~g/mol. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:

2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3

I hope it helps!

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