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LUCKY_DIMON [66]
4 years ago
10

A chemistry student needs of isopropenylbenzene for an experiment. She has available of a w/w solution of isopropenylbenzene in

carbon tetrachloride. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Chemistry
1 answer:
zhenek [66]4 years ago
8 0

The question is incomplete, here is the complete question:

A chemistry student needs 10.00 g of isopropenylbenzene for an experiment. She has available 120. g of a 42.7 % w/w solution of isopropenylbenzene in carbon tetrachloride. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

Round the answer to 3 significant digits.

<u>Answer:</u> The mass of solution that the student should use is 23.4 grams

<u>Explanation:</u>

We are given:

42.7 % (w/w) solution of isopropenylbenzene.

This means that 42.7 grams of isopropenylbenzene is present in 100 grams of solution.

To calculate the mass of solution when 10.00 g of isopropenylbenzene is needed, we apply unitary method:

For 42.7 grams of isopropenylbenzene, the amount of solution needed is 100 grams

So, for 10.00 grams of isopropenylbenzene, the amount of solution needed will be = \frac{100}{42.7}\times 10=23.4g

Hence, the mass of solution that the student should use is 23.4 grams

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How many grams of CaCl2 are in 250 mL of 2.0 M CaCl2?
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The answer is:  " 56 g CaCl₂ " .
__________________________________________________________

Explanation:
__________________________________________________________
2.0 M CaCl₂  = 2.0 mol CaCl₂ / L  ; 

Since: "M" = "Molarity" (measurement of concentration); 

                  = moles of solute per L {"Liter"} of solution.
__________________________________________________________
Note the exact conversion:  1000 mL = 1 L . 

Given: 250 mL ;   

250 mL = ?  L  ?  ;  


250 mL * (1 L / 1000 L) =  (250/1000) L = 0.25 L . 
___________________________________________________________
 
(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol  = 0.50 mol CaCl₂ ;

We have: 0.50 mol CaCl₂ ;  Convert to "g" (grams):

→ 0.50 mol CaCl₂  .
___________________________________________________________
1 mol CaCl₂ = ? g ?

From the Periodic Table of Elements:

1 mol Ca = 40.08 g

1 mol Cl  =  <span>35.45 g .
</span>
There are 2 atoms of Cl in " CaCl₂ " ;  

→ Note the subscript, "2", in the " Cl₂ " ; 
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So, to calculate the molar mass of "CaCl₂" :

40.08 g  +  2(35.45 g) = 

40.08 g  +  70.90 g = 110.98 g ;  round to 4 significant figures; 

                                 → round to 111 g/mol .
__________________________________________________________
So:

→  0.50 mol CaCl₂  = ? g CaCl₂  ? ; 

→  0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;

                                             = (0.50) * (111 g) CaCl₂ ;

                                             =  55.5 g CaCl₂  ;

                                                → round to 2 significant figures; 

                                                →  56 g CaCl₂ .
___________________________________________________________
The answer is:  " 56 g CaCl₂ " .
___________________________________________________________
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