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nika2105 [10]
4 years ago
7

When balancing a chemical equation, what are the large numbers that we adjust?

Chemistry
1 answer:
Nata [24]4 years ago
6 0

Answer:

Coefficients

Explanation:

Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

H₂ + Cl₂     =>       HCl

Reactants:          Products:

2 hydrogen         1 hydrogen

2 chlorine            1 chlorine

Write the coefficient 2 in the products.

H₂ + Cl₂     =>       2HCl

Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.

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7 0
4 years ago
Sonni added 23.79 mL of KOH to 20.00 mL of 0.393 M HF until the equivalence point was reached. What is the concentration of conj
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Answer:

0.1795 M

Explanation:

From the given information:

The equation is:

\mathbf{HF_{(aq)}+ KOH_{(aq)} \to KF _{(aq)} + H_2O}

From the above equation, the reaction will go to completion due to the strong base:

At the equivalence point, moles of acid (HF) will be equal to moles of base (KOH)

\text{Number of moles = Volume}  \times Molarity

Thus. since moles of HF = moles of KOH

Then; 0.020 × 0.393 M = 0.02379 × (x) M

(x) M = \dfrac{0.02 \times 0.393 \ M}{0.02379}

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Using the balanced neutralization reaction;

moles of HF = moles of KOH = moles of conjugate base = 0.00786 mol

∴

Volume = 0.020 L + 0.02379 L

Volume = 0.04379 L

Volume of the solution =  0.04379 L

Therefore; Molarity = \dfrac{moles}{volume}

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Molarity = 0.17949 mol/L

= 0.1795 M

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3 years ago
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