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nika2105 [10]
4 years ago
7

When balancing a chemical equation, what are the large numbers that we adjust?

Chemistry
1 answer:
Nata [24]4 years ago
6 0

Answer:

Coefficients

Explanation:

Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

H₂ + Cl₂     =>       HCl

Reactants:          Products:

2 hydrogen         1 hydrogen

2 chlorine            1 chlorine

Write the coefficient 2 in the products.

H₂ + Cl₂     =>       2HCl

Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.

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What is the empirical formula of Fe?
Lera25 [3.4K]

Answer:

The ratio is 1.000 mol of iron to 1.500 mol of oxygen (Fe1O1.5). Finally, multiply the ratio by two to get the smallest possible whole number subscripts while still maintaining the correct iron-to-oxygen ratio: The empirical formula is Fe2O3.

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Vanadium (IV) carbonate
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Answer:

Explanation:

1) Vanadium (IV) → V⁺⁴

Carbonate → CO₃⁻²

So , Vanadium (IV) Carbonate = V₂(CO₃)₄  or V(CO₃)₂

2) Tin (II) = Sn⁺²

Nitrite = NO₂⁻

So, Tin (II) Nitrate = Sn(NO₂)₂

3) Cobalt (III) = Co⁺³

Oxide = O⁻²

So , Cobalt (III) Oxide = Co₂O₃

4) Titanium (II) = Tn⁺²

Acetate = CH₃COO⁻

So , Titanium (II) Acetate = Tn(CH₃COO)₂ or Tn(C₂H₃O₂)₂

5) Vanadium (V) = V⁺⁵

Sulfide = S⁻²

So , Vanadium (V) Sulfide = V₂S₅

6) Chromium (III) = Cr⁺³

Hydroxide = OH⁻

So , Chromium (III) Hydroxide = Cr(OH)₃

7) Lithium = Li⁺

Iodide = I⁻

So , Lithium Iodide = LiI

8) Lead (II) = Pb⁺²

Nitride = N⁻³

So , Lead (II) Nitride = Pb₃N₂

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Bromide = Br⁻

So , Silver Bromide = AgBr

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3 years ago
A physical property that is unique to metals and crystals is
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The answer: hardness
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4 years ago
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A sample of iron with a mass of 50.0 grams absorbs 2500 J of thermal energy. How much would the temperature of this sample chang
ella [17]

Temperature change would be 112.6° C.

<u>Explanation:</u>

We can find the amount or heat absorbed or emitted during any reaction by finding the product of their mass, specific heat, and change in temperature of the metal.

Mass of the iron, m = 50.0 g

Amount of heat absorbed, q = 2500 J

Change in temperature, ΔT = ?

Specific heat of Iron, C = 0.444 J/g °C

\boldsymbol{q}=\boldsymbol{m} \times \boldsymbol{C} \times \boldsymbol{\Delta} \mathbf{T}

Plugin the values and rearrange the equation to get the change in temperature as,

\Delta \mathbf{T}=\frac{\mathbf{q}}{c \times m}

\Delta \mathrm{T}=\frac{2500 \mathrm{J}}{0.444 \frac{J}{\mathrm{g}^{\circ} \mathrm{C}} \times 50 \mathrm{g}}=112.6^{\circ} \mathrm{C}

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Answer:

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