To solve this problem, it is necessary to apply the ideal Gas equations, as well as the calculation equations of the weight difference, which under the comparison of two values.
By definition we know that the ideal gas equation is given by the equation,
PV = nRT
Where,
P = Pressure
V = Volume
R = Gas ideal constant
T = Temperature
n = number of moles
Our values are given by
![P = 1.1013*10^5Pa](https://tex.z-dn.net/?f=P%20%3D%201.1013%2A10%5E5Pa)
![T = 31.5\°C = 304.5K](https://tex.z-dn.net/?f=T%20%3D%2031.5%5C%C2%B0C%20%3D%20304.5K)
![\rho = 1.2074kg/m^3](https://tex.z-dn.net/?f=%5Crho%20%3D%201.2074kg%2Fm%5E3)
PART A) Using this previous equation we can find the number of moles per Volume, that is
![PV = nRT](https://tex.z-dn.net/?f=PV%20%3D%20nRT)
![\frac{n}{V} = \frac{P}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7BV%7D%20%3D%20%5Cfrac%7BP%7D%7BRT%7D)
Replacing with our values
![\frac{n}{V} = \frac{1.013*10^5}{(8.314)(304.5)}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7BV%7D%20%3D%20%5Cfrac%7B1.013%2A10%5E5%7D%7B%288.314%29%28304.5%29%7D)
![\frac{n}{V} = 40.014mol/m^3](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7BV%7D%20%3D%2040.014mol%2Fm%5E3)
PART B ) We can calculate the number of moles of 1m^3 through Avogadro number, then
![M = nA](https://tex.z-dn.net/?f=M%20%3D%20nA)
![M = 40.014*(2.88*10^{-2})](https://tex.z-dn.net/?f=M%20%3D%2040.014%2A%282.88%2A10%5E%7B-2%7D%29)
![M = 1.1524Kg](https://tex.z-dn.net/?f=M%20%3D%201.1524Kg)
Therefore in
there are 1.1524Kg of Gas.
PART C ) Density can be defined as the proportion of mass in a specific quantity of Volume, then
![\rho_2 = \frac{M}{V}](https://tex.z-dn.net/?f=%5Crho_2%20%3D%20%5Cfrac%7BM%7D%7BV%7D)
![\rho_2 = \frac{1.1524}{1}](https://tex.z-dn.net/?f=%5Crho_2%20%3D%20%5Cfrac%7B1.1524%7D%7B1%7D)
![\rho_2 = 1.1524kg/m^3](https://tex.z-dn.net/?f=%5Crho_2%20%3D%201.1524kg%2Fm%5E3)
The difference of percentage then is
![\Delta \rho = \frac{\rho_1-\rho_2}{\rho_2}*100\%](https://tex.z-dn.net/?f=%5CDelta%20%5Crho%20%3D%20%5Cfrac%7B%5Crho_1-%5Crho_2%7D%7B%5Crho_2%7D%2A100%5C%25)
![\Delta \rho = \frac{1.2074-1.1524}{1.1524}*100\%](https://tex.z-dn.net/?f=%5CDelta%20%5Crho%20%3D%20%5Cfrac%7B1.2074-1.1524%7D%7B1.1524%7D%2A100%5C%25)
![\Delta \rho = 0.0477*100\%](https://tex.z-dn.net/?f=%5CDelta%20%5Crho%20%3D%200.0477%2A100%5C%25)
![\Delta \rho = 4.77\%](https://tex.z-dn.net/?f=%5CDelta%20%5Crho%20%3D%204.77%5C%25)
YES, because as the percentage is less than 10%, the calculated value agrees with the stated value.
Answer:
Inertia is the reason that people in cars need to wear seat belts. Instead, the riders continue moving forward with most of their original speed because of their inertia. If the driver is wearing a seat belt, the seat belt rather than the windshield applies the unbalanced force that stops the driver's forward motion.
Answer:
The answer is explained below.
Explanation:
All the point on the disk has same angular acceleration. Here, the point P is at the midway between the center and the rim of the disk and the point Q is at rim of the disk.
So, the distance of the point Q from the axis is twicee the distance of the point P from the axis.
<em>Rp - R</em>
<em>Rq - 2R</em>
The linear acceleration is
α2 - Rα
So, the linear acceleration of Q is twice as great as the linear acceleration of P.
The speed of the particle when it is in the circular motion depends on the radius of the particle.
In this case, the speed of point Q is twice the speed of point P.
Answer:
The white dwarf undergoes a catastrophic collapse, leading to a type of supernova that is somewhat different from that which occurs in a massive star but is comparable in energy.
Hope this help:)
Answer:
b, an element
Explanation:
this is because you never combined it with any other element in the periodic table and gold is not a compound or mixture.