Answer:
<em>The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum</u>
The total momentum of a system of bodies is conserved unless an external force is applied. The formula for the momentum of a body with mass m and velocity v is:
P=mv.
If we have a system of bodies, then the total momentum is the sum of them all
If a collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses, the law of conservation of linear momentum is:
According to the conditions of the problem, two persons standing on a frictionless surface are initially at rest (v1=0, v2=0). Their masses are m1=50 Kg and m2=65 Kg. After the push, one person (say m1) moves backward at v1'=-1.1 m/s. We can calculate the speed of the other person by solving for v2':
Substituting:
The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.
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All your stating is the question, you don't have any answers to choose from or a question?
Momentum (P) = Mass (kg) * Velocity (m/s)
P = M * V
P = 50 * 5
P = 250
So momentum is 250 kgm/s