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Nina [5.8K]
3 years ago
15

What are the various adverse effects of chemistry​

Chemistry
1 answer:
Kisachek [45]3 years ago
4 0

<u>Answer:</u>

<em>Chemistry is the reaction between certain elements to </em><em>create a new compound</em><em> which may happen naturally but is mostly man made and hence has lot of good as well as </em><em>adverse effects.</em>

<u>Explanation:</u>

The <em>product or compound</em> that we get and the energy or outcome we receive is the ultimate result that decides whether chemical reaction that has happened is good or bad.

There are reactions that may cause pain and suffering to living beings and  are also able to<em> Infuse damage and destruction</em> are are adverse nature. they can also change the course of nature hence are are <em>dangerous. </em>

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The diagram is an example of which of the following..
Evgesh-ka [11]

Thats an alkane.

Option  B.

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2 years ago
How many moles of Oxygen atoms are in a sample of 3.98 x 10^23 atoms?
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8 0
3 years ago
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Se sabe que 10 g de calcio reaccionan con 4 g de oxígeno para obtener 14 g de óxido de calcio. Indica la cantidad de óxido de ca
egoroff_w [7]

Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

2Ca+O_2\rightarrow 2CaO

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

4 0
3 years ago
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Maybe that will help you answer the question.

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