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netineya [11]
3 years ago
10

Problem PageQuestion Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume

of carbon tetrachloride would be produced by this reaction if of chlorine were consumed?
Chemistry
1 answer:
IgorC [24]3 years ago
8 0

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.

Be sure your answer has the correct number of significant digits.

Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm  (at STP)

V = Volume of gas = 3.16 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K=

n=\frac{PV}{RT}

n=\frac{1atm\times 3.16L}{0.0820 L atm/K mol\times 273K}=0.141moles

CH_4+4Cl_2\rightarrow 4HCl+CCl_4

According to stoichiometry:

4 moles of chlorine produces = 1 mole of carbon tetrachloride

Thus 0.141 moles of methane produces = \frac{1}{4}\times 0.141=0.0352 moles of carbon tetrachloride

volume of carbon tetrachloride =moles\times {\text {Molar volume}}=0.0352mol\times 22.4L/mol=0.788L

Thus volume of carbon tetrachloride that would be produced is 0.788 L

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Explanation:

We are given;

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We are required to determine the mass of fats removed in pounds.

We need to know that;

Density = Mass ÷ volume

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Rearranging the formula;

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but, 1 pound = 453.592 g

Therefore;

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The complete question is below:

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