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1 year ago

Just need these six questions answered for math :>

Mathematics

1 answer:

8_murik_8 [283]1 year ago

3 0

Answer:

here for answer to

Step-by-step explanation:

lol

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Which of the following possibilities will NOT form a triangle? (5 points)

ruslelena [56]

<h3>Answer: Choice A</h3>

Side = 5 ft, side = 15 ft, side = 3 ft

Explanation:

The two sides 5 ft and 3 ft add to 5+3 = 8 ft which is not larger than the 15 ft side. This is exactly why a triangle is not possible here.

If we want a triangle to happen, then adding any two sides must be larger than the third side.

If we want a triangle with sides a,b,c, then we need the following to be true

a+b > c
a+c > b
b+c > a

Refer to the triangle inequality theorem for more information.

3 0

2 years ago

Can someone please help me with math.

Mariana [72]

Answer:

12) 26x^2+22x+25

13) -15x^2-21x-11

14) x^2+32x+18

15) 9x^6+10x^5-15x^4+14

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Lauren bought g golf balls. The balls came in 10 packages. Write an expression that shows how many golf balls were in each packa

mezya [45]

G/10
g amount into 10 different sections.

6 0

2 years ago

Find the value of x

Svet_ta [14]

Answer:

$150^o$

Step-by-step explanation:

<u>Step 1: Distribute the plus</u>

<u /> $(x + 15)^o + (135 - x)^o$

$x + 15 + 135 - x$

<u>Step 2: Combine like terms</u>

<u /> $x + 15 + 135 - x$

$(x - x)^o + (15 + 135)^o$

$0 + 150^o$

$150^o$

Answer: $150^o$

7 0

2 years ago

Read 2 more answers

There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,

lys-0071 [83]

According to given information there are :

5 red balls

4 blue balls

6 yellow balls

10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{total \: red \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{25}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{1}{5}$

<h3>2. what is the probability that the ball chosen is blue ?</h3>

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{total \: blue \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{25}$

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{total \: yellow\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{25}$

<h3>4. what is the probability that the ball chosen is green ?</h3>

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{total \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{25}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{2}{5}$

<h3>5. what is the probability that the ball chosen is not green ?</h3>

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{total \: non \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{15}{25}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{3}{5}$

3 0

1 year ago