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solniwko [45]
2 years ago
9

Find m∠E *geometry problem*

Mathematics
1 answer:
Arada [10]2 years ago
4 0
8x+4=9x-5
when you solve that out you get x =9
then you plug in x everywhere in the chart

3(9)=27
9(9)-5=76
180-76-27= 77°

angle E =77°

please mark brainiest if you can
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Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
50 POINTS Vanessa has 6 dimes and 2 pennies. Joachim has 1 dollar, 3 dimes, and 5 pennies. Jimmy has 5 dollars and 7 pennies. Th
Yakvenalex [24]

Vanessa: a dime = 10 cents = 0.10

A penny = 1 cent = 0.01

6 x 0.10 = 0.60

2 x 0.01 = 0.02

Total = 0.60 + 0.02 = 0.62

Joachim : a dollar = 1.00

3 x 0.10 = 0.30

5 x 0.01 = 0.05

Total = 1.00 + 0.30 + 0.05 = 1.35

Jimmy: total = 5.00 + 0.07 = 5.07

Total of all 3: 0.62 + 1.35 + 5.07 = $7.04

This is less than $8 so they don’t have enough.

They need: 8.00 - 7.04 = $0.96 more

3 0
3 years ago
Read 2 more answers
For which interval does this quadratic inequality hold true?
adoni [48]

Answer:

D

Step-by-step explanation:

x²-4x-12≤0

x²-6x+2x-12≤0

x(x-6)+2(x-6)≤0

(x-6)(x+2)≤0

x=6,-2

∴ value of x lies between -2 & 6

3 0
11 months ago
Ippppppppppppppppppopkokhiufytedfliyhuigjboihlk.h
Lemur [1.5K]

Answer:

it b

Step-by-step explanation:

5 0
2 years ago
Figure abcd is a parallelogram what is the value of x 5x +3 38
defon
5x + 3 = 38
5x = 38 + 3
5x = 35
x = 35/5
x = 7
4 0
3 years ago
Read 2 more answers
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