Question

Kendra has $3.15 in dimes and nickels. If she has 4 times as many dimes as nickels, how many of each coin does she have?

Answer 1

• It is important to note that:

A nickel = $0.05

A dime = $0.10

We would be representing,

The number of nickels =  n

The number of dimes = d

• Kendra has $3.15 in dimes and nickels. Writing this statement as an algebraic expression:

0.05n + 0.10d = 3.15...............Equation 1

• She has 4 times as many dimes as nickels. The algebraic expression for this statement :

4n = d ........................................ Equation 2

We would substitute 4n for d in Equation 1

0.05n  + 0.10 x 4n = 3.15...............Equation 3

0.05n + 0.4n = 3.15

0.45n = 3.15

Divide both sides by 0.45

0.45n/0.45 = 3.15/0.45

n = 7

The number of nickels is 7

We solve for d, the number of dimes

4n = d

n = 7

4 x 7 = d

28 = d

The number of dimes is  28

Therefore, Kendra has 7 nickels and 28 dimes

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