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3 years ago

How to memorise times tables

1 answer:

6 0

Its very hard to memorise them but if you practice and keep practicing you might get the hang of them. But heres a little trick alright? For the 11ths tables every except 12 will be 11,22,33 etc.. for instance 5 times 11 equals 55 or 8 times 11 equals 88.

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Please help me asap!!!!!!

padilas [110]

Answer:

z-12

Step-by-step explanation:

you start of by z baseball and i know for a fact that fewer means subtraction so the answer is z-12

3 0

2 years ago

15 points PLEASE HELP , and be careful when answering !!

Aleks04 [339]

18.84 because the formula to find the volume of a cone is pie*r^2*h/3 and your radius is 3 and the height is 2, so if you plug those in the equation and calculate it this should be your answer

6 0

3 years ago

A taxi charges a flat rate of R10, and an additional cost of 30 cents per kilometer. If you have

Maslowich

Step-by-step explanation:

so, just by getting into the taxi we have to pay R10.

that leaves us 22 - 10 = R12 for the actual trip.

30 cents per kilometer.

so, how many units of 30 cents are there in R12 ? that is the number of kilometers we can go.

R12 = 1200 cent (right ?)

1200 / 30 = 120 / 3 = 40

so, we can travel 40 kilometers for that money.

8 0

2 years ago

If a football team has a 90% chance of making a field goal for 3 points and a 35% chance of making a touchdown for 7 points, fin

Svetlanka [38]

2.7 points (my guess)

4 0

3 years ago

Read 2 more answers

Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w

Arte-miy333 [17]

Let $k$ be an integer. Suppose there is a triangle with legs of length 16 and $2k+1$ . Then by the Pythagorean theorem, the length of the hypotenuse should be

$\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}$

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if $x=16$ and $y=2k+1$ are integers, then so are $x^2-y^2$ , $2xy$ , and $x^2+y^2$ .

However, $4k^2+4k+257$ is not a perfect square trinomial, which means for any integer $k$ , the length of the hypotenuse is not an integer, so such a triangle doesn't exist.

4 0

3 years ago