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slava [35]
2 years ago
14

if the circumference of a circle measures 3π cm, what is the area of the circle in terms of π? A) 3 4 π cm2 b) 3 2 π cm2 c) 9 4

π cm2 d) 9 2 π cm2
Mathematics
2 answers:
JulijaS [17]2 years ago
6 0

The circumference of a circle is given by

C = 2\pi r

Where r is the radius of the circle. So, you have

3\pi = 2\pi r \iff 2r = 3 \iff r = \dfrac{3}{2}

The area of a circle is given by

A = 2\pi r^2

If you plug the value for r you have

A = 2 \pi \left(\dfrac{3}{2}\right)^2 = 2\pi\dfrac{9}{4} = \dfrac{9}{2}\pi

zavuch27 [327]2 years ago
6 0

C = 2*π*r

3π = 2π*r

\frac{3\pi }{2\pi } = \frac{2\pi *r}{2\pi }

\frac{3}{2} = r

A = π * r²

   = π (\frac{3}{2} )^{2}

   = π (\frac{9}{4} )

Answer: C

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(-6,1) after a translation of (x-2y)
zysi [14]

Answer:

(-8,1)

Step-by-step explanation:

Imma assume you meant (x-2, y)

x coordinate becomes -6-2=-8

y coordinate stays the same

so the image is (-8,1)

5 0
1 year ago
Find the area between y=(x-2)ex and the x-axis from x=2 to x=4.
mojhsa [17]

Answer:

e^4+e^2

Step-by-step explanation:

It can be found by integral.

First let's find the intersection points.

(x-2)e^x = 0

Only intersection point is x = 2.

And it is asked to find the area in the interval (2, 4).

\int\limits^4_2 (x-2)e^x \,dx=?

We will use integration by parts.

x-2=u\\dx=du\\e^xdx=dv\\e^x=v

\int\limits^4_2 (x-2)e^x \,dx=uv-\int vdu=(x-2)e^x-\int e^xdx=(x-2)e^x-e^x=\\\\=(x-3)e^x|^4_2=(4-3)e^4-(2-3)e^2=e^4+e^2

3 0
3 years ago
Kira has to carry 170 apples from a farm to the market. How many baskets will she need, given that each basket can hold 46 apple
Helga [31]

Answer:

4 baskets

Step-by-step explanation:

Since 170 divided by 46 equals 3 with a remainder of 32, you use the remainder,32, and change it to one more basket so 3+1=4 so Kira needs 4 baskets.

7 0
2 years ago
Read 2 more answers
Write the equation of a parabola with focus at (1,-4) and a directrix at X=2
konstantin123 [22]

Answer:

The equation of a parabola is

x =  \frac{1}{4(f - h)} (y - k) ^{2}  + h

Step-by-step explanation:

(h,k) is the vertex and (f,k) is the focus.

Thus, f = 1, k = −4.

The distance from the focus to the vertex is equal to the distance from the vertex to the directrix: f - h = h - 2.

Solving the system, we get h = 3/2, k = -4, f = 1.

The standard form is:

x =  -  \frac{y ^{2} }{2}  - 4y -  \frac{13}{2}

The general form is:

2x +  {y}^{2}  + 8y + 13 = 0

The vertex form is:

x =  -  \frac{(y + 4) ^{2} }{2}  +  \frac{3}{2}

The axis of symmetry is the line perpendicular to the directrix that passes through the vertex and the focus: y = -4.

The focal length is the distance between the focus and the vertex: 1/2.

The focal parameter is the distance between the focus and the directrix: 1.

The latus rectum is parallel to the directrix and passes through the focus: x = 1.

The length of the latus rectum is four times the distance between the vertex and the focus: 2.

The eccentricity of a parabola is always 1.

The x-intercepts can be found by setting y = 0 in the equation and solving for x.

x-intercept:

( -  \frac{13}{2}  \: ,0)

The y-intercepts can be found by setting x = 0 in the equation and solving for y.

y-intercepts:

(0, - 4 -  \sqrt{3)}

(0, - 4 +  \sqrt{3)}

3 0
2 years ago
If EG=50,and point F is 2/5 of the way between E and G
TEA [102]
2/5 of 50 is 20. 50-20=30. Making FG=30

7 0
3 years ago
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