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2 years ago

How do I find the triangles similarity and each length

Mathematics

1 answer:

Kamila [148]2 years ago

7 0

Angle g would be congruent/equal to itself because of verticals angles theorem. i hope that helped a bit

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A square rug is 11m^2 the bedroom for the rug is 4m by 5m will the rug fit? Explain why

vekshin1

Yes it will fit

Step-by-step explanation:

the square rug is $11m^{2}$

so each side is $\sqrt{11m^{2} } =3.31m$

and the bedroom is $4m*5m$

so it will fit

6 0

3 years ago

Read 2 more answers

Find the greatest common factor of 10, 30 and 45

lawyer [7]

Answer:

The greatest common factor is 5.

Step-by-step explanation:

The prime factorisation of 10, 30 and 45 is,

10 = 2 × 5

30 = 2 × 3 × 5

45 = 3 × 3 × 5

The prime factor '5' is common in the factorisation of 10, 30 and 45

So, the greatest common factor of 10, 30 and 45 is 5.

5 0

2 years ago

Two adjacent sides of a parallelogram are 6mm and 10mm respectively, and they form an angle measuring 60. Find the area of the p

Snowcat [4.5K]

Answer:

51.96 mm² approximately

Step-by-step explanation:

the first thing you should know is that the area of a rectangle is base*height sin of (

the included angle i.e

Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°

Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:

Aparallelogram= bh sin of sin of the included angle

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately

4 0

2 years ago

Hank has to drain his pool so repairs can be done on a crack on the bottom. The company coming to fix the pool is scheduled to a

Alik [6]

Answer:

The answer to the question: "Will Hank have the pool drained in time?" is:

Yes, Hank will have the pool drained in time.

Step-by-step explanation:

To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:

Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
Available time = 360 minutes

Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:

Volume of the pool = Deep * Long * Wide
Volume of the pool = 2 m * 10 m * 8 m
Volume of the pool = 160 m^3

Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:

1 m^3 = 264.172 gal

Now, we use a rule of three:

If:

1 m^3 ⇒ 264.172 gal
160 m^3 ⇒ x

And we calculate:

$x = \frac{160 m^{3}*264.172 gal }{1m^{3} }$ (We cancel the unit "m^3)
x = 42267.52 gal

At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:

Time to drain the pool = $\frac{42267.52gal}{130\frac{gal}{min} }$ (We cancel the unit "gallon")
Time to drain the pool = 325.1347692 minutes
Time to drain the pool ≅ 326 minutes (I approximate to the next number because I want to assure the pool is drained in that time)

As we know, Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes.

7 0

2 years ago

Write the place value of the underlined digit round each number to the place of the underlined digit.

fiasKO [112]

Answer:

3.0.8

4.8

5.11.51

Step-by-step explanation:

8 0

3 years ago