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Juli2301 [7.4K]
3 years ago
7

Evaluate each expression for x = 6 and for x = 3. Based on your results, do you know whether the two expressions are equivalent?

Mathematics
1 answer:
cluponka [151]3 years ago
6 0

You can't add the same number to 2 different numbers and get the same answer, so no.

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Diff Eq dy/dx= (ycos(x))/(1+y^2) initial condition is y(0)=1 work below ...?
Volgvan
Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
5 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
Write me a paragraph proof.
elixir [45]
Just write all of that but instead of in the box between each statement and reason write if then
4 0
3 years ago
GUYS PLEASE HELP
Volgvan

Answer:

10 minutes

Step-by-step explanation:

Since you can do 6 flyers each minute, the rate would go at 6x, with x being minutes. You initially did 80, so the equation for you would be y=6x+80.

Your friend's equation would be y=4x+100, because he initially had 100 done and is now getting 4 done per minute.

If you put the 2 equations in your calculator, the intersection will happen at x=10, showing that you and your friend will have an equal number of flyers at 10 minutes.

3 0
3 years ago
What is a rational number that isn't an integer?
katen-ka-za [31]
An integer is like -5,-4,-3,-2,-1,0,1,2,3,4...
all counting numbers plus 0 and negatives

so no fractions
so an an easmple of a rational number that is not an integer is any fraction a/b such that it doesn't sipmlify to an integer

examples
2/3
1/4
5/6
9/10
etc
6 0
4 years ago
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