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VARVARA [1.3K]
3 years ago
15

Let h(x)=

ddle" class="latex-formula"> and k(x)=2x+7

Find the value of h(k(3))
Mathematics
1 answer:
PolarNik [594]3 years ago
7 0
So if we have h(x) if multiplication isolate k-3andx-6 2x-3 = 6+7=13 value=62
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fredd [130]
Hi there I know the answer but it was confusing so it has to be D or B
6 0
2 years ago
Could anyone find this?
lina2011 [118]

Answer:

Step-by-step explanation:

Since the squares have areas of 32u^2. The side lengths are

s=\sqrt{32}\\ \\ \text{By the Pythagorean Theorem}\\ \\ x^2=s^2+s^2\\ \\ x^2=32+32\\ \\ x^2=64\\ \\ x=\sqrt{64}\\ \\ x=8

8 0
2 years ago
How to write Eight more than four times a number is -12 as an equation
Ivenika [448]

Step-by-step explanation:

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2 years ago
A 5.1-ft-tall person walks away from a 12-ft lamppost at a constant rate of 3.9 ft/sec. What is the rate that the tip of the per
nekit [7.7K]

Answer:

6.78ft/sec

Step-by-step explanation:

From the question, dx/dt= 3.9 ft/sec

We are looking for Dy/dt

From geometry,vof this case the relationship between x and y is needed here, there is two similar triangle that exhibited by the man and the lamb

12/y= 5.1/(y-x)

Then ,cross multiply, we have

12(y-x)=5.1y

12y-12x=5.1y

12y-5.1y=12x

6.9y=12x

y=( 12/6.9)x

Differentiating implicitly the bother sides with respect to t, we have

Dy/dt= ( 12/6.9)dx/dt

But dx/dt= 3.9 ft/sec

Then Dy/dt= ( 12/6.9)× 3.9

Dy/dt=6.78ft/sec

Hence, the rate that the tip of the person's shadow moves away from the lamppost when the person is 9 ft away from the lampost is 6.78ft/sec

CHECK THE ATTACHMENT FOR THE FIQURE

6 0
2 years ago
The net of a solid figure is shown below:
hammer [34]

Answer:

D, 6 x 3 x 3

Step-by-step explanation:

One area of a square is 3 x 3 there are 6 squares so we multiply by 6 too.

4 0
3 years ago
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