Its d. i took the k12 test.
d. The temperature steadily decreases before it levels off briefly. Then the temperature steadily decreases at a slower rate for the same amount of time as it decreased initially. After reaching its lowest temperature of the night, the temperature begins to steadily increase. When the temperature gets close to the same temperature it started at, the temperature levels off and remains the same.
Answer: p= $8 s= $2.50
Step-by-step explanation:
3p + 4s = 34 and 3p + 7s= 41.50
Since the number of pizzas DIDNT change between these two equations, we can use the total of the second equation to help us find the price of one sandwich.
41.50 - 34 = $7.5 for 3 sandwiches (7s-4s)
So how much is one sandwich? 7.50/3 = $2.50 for each sandwich
now that we know s, it’ll be much easier finding p. We can use one equation to find p.
3p + 4(2.5) = 34 (Solve algebraically)
3p + 10 = 34
- 10 | -10
3p = 24
3p/3 = 24/3
p = $8. Now you can check by substituting the variables!
40 cups, 16+16=32, 32+1/2 16=40, 16÷2=8:) hope i helped
Answer:
7.2/3 ± (isqrt2)/3
8.2±i
9.-0.4±0.2
10.1/3±1/3sqrt19
Step-by-step explanation:
7. a =3, b=-4, c=2
plugging in to the quadratic formula
(2 ± isqrt2)/3
8.a=1,b=-4.c=5
plugging in to the quadratic formula
2±i
9.a=5,b=4,c=2
plugging in to the quadratic formula
-0.4±0.2
10.a=-3,b=2,c=6
plugging in to the quadratic formula
1/3±1/3sqrt19