Answer:
Step-by-step explanation:
(a) 3 of the 6 numbers on the die are even, so the probability that one of them will show is 3/6 = 1/2.
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(b) 2 of the 6 numbers on the die are less than 3, so the probability that one of them will show is 2/6 = 1/3.
The number of possible groups or combination of three men can be formed from 10 is 120.
According to the given question.
Total number of men in a company, n = 10.
Number of men to be selected, r = 3
As we know that, What is a combination in math?
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A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter.
Therefore, the number of possible groups or combination of three men can be formed from 10
=
= 10!/ 3!7!
= 10(9)(8)/3(2)
= 5 × 3 × 8
= 120
The number of possible groups or combination of three men can be formed from 10 is 120.
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The illegal values of b are when the denominator equals 0.
So, gives you (b-4)(b+2)=0
Therefore, b=4 and b=-2, which is answer A.