Answer:
muddy water is a heterogeneous mixture, which is Suspension.
As the first astronaut throws the ball, lets assume it goes with v velocity and the mass of the ball be m
the momentum comes out be mv, thus to conserve that momentum the astronaut will move opposite to the direction of the ball's motion with the velocity mv/M (where M is the mass of the astronaut).
B) All nonzero digits are significant.
Answer:
0.280 s
Explanation:
I set it up as 5.22=(55)(0.0266)/x and then solved for x to be 2.80.
Acceleration= change in speed/ change in time
30-10= 20 (change in speed)
Time= 10 seconds
20/10= 2
Acceleration= 2 m/s^2
Hope this helps! :)