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andreyandreev [35.5K]
2 years ago
10

3. What is the potential difference across a 1 500 12 resistor carrying a

Physics
1 answer:
gregori [183]2 years ago
6 0

The potential difference across a 1500 ohm resistor carrying a current of 0.075 A is approx. equal to 113 V.

Explanation:

An ideal electrical circuit obeys Ohm's law. As per this law, the potential difference in any electrical circuit will be directly proportional to the current flowing in that circuit. And the proportionality constant is the resistance offered by the circuit.

V = I * R

As here, the current is said to be carried as 0.075 A and the resistance is 1500 ohm, then the potential difference will be

V = 0.075 * 1500 =112.5 = 113 V

Thus, the potential difference across a 1500 ohm resistor carrying a current of 0.075 A is approx. equal to 113 V.

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Answer:

the element that takes part in a chemical reactions

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except decomposition reactions

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3 years ago
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What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic
VladimirAG [237]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   v_w  =  2.256 *10^{8} \  m/s

B

  v_e  =  2.21 *10^{8} \  m/s

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  n_w  =  1.33

      The  refractive  index of ethanol is  n_e  =  1.36

       

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       v_w  =  \frac{c}{n_w }

Where  c is the speed of light with value  c =  3.0 *10^{8} \  m/s

       v_w  =  \frac{3.0 *10^{8}}{1.33 }

       v_w  =  2.256 *10^{8} \  m/s

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            v_e  =  \frac{ c}{n_e }

  =>       v_e  =  \frac{3.0 *10^{8}}{1.36 }

=>          v_e  =  2.21 *10^{8} \  m/s

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Which one is having lesser ressistance. a 60w bulb or a 40w bulb?
Ivan
Power dissipation = (voltage across the component)² / (resistance of the component)

Since the resistance is in the denominator of the fraction in this formula for the
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So the <u>60w bulb</u> has lower resistance than the 40w bulb.
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