In an RC series circuit, ε = 12.0 V, R = 1.25 MΩ, and C = 1.42 µF. (a) Calculate the time constant. (b) Find the maximum charge
1 answer:
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Answer:
v = 384km/min
Explanation:
In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.
You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:
You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:
hence, the speed of the Hubble is approximately 384km/min
Answer:
the final kinetic energy is 0.9eV
Explanation:
To find the kinetic energy of the electron just after the collision with hydrogen atoms you take into account that the energy of the electron in the hydrogen atoms are given by the expression:
you can assume that the shot electron excites the electron of the hydrogen atom to the first excited state, that is
-10.2eV is the energy that the shot electron losses in the excitation of the electron of the hydrogen atom. Hence, the final kinetic energy of the shot electron after it has given -10.2eV of its energy is: