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3 years ago

Classify the measurement 80 blocks north.

Physics

1 answer:

Tasya [4]3 years ago

4 0

Answer:

Vector quantity

Explanation:

-A vector quantity refer to the physical quantity characterized by the presence of both magnitude as well as direction.

-The direction is given as North.

-The magnitude is given as 80 blocks.

#Hence, this is a vector quantity.

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Assuming the average rate of heat energy flowing outwards from earth to be 0.063 W/m2 calculate the energy available at a hot sp

MaRussiya [10]

Answer:

"13.48 Kwhr" is the right solution.

Explanation:

The given values are:

Average rate of heat energy,

= 0.063 W/m²

Diameter,

= 8m

Efficiency of conversion,

= 50%

Now,

The area of hotspot will be:

⇒ $A=\frac{\pi}{4} d^2$

On substituting the values, we get

⇒ $=\frac{3.14}{4} (8)^2$

⇒ $=0.785\times 64$

⇒ $=50.24 \ m^2$

Total heat generation rate will be:

⇒ $Q=q\times A$

$=0.063\times 50.24$

$=3.16 \ W$

hence,

The electricity generation capacity will be:

⇒ $P=\eta Q t$

On substituting the values, we get

⇒ $=0.5\times 3.16\times 8760$

⇒ $=13840.8 \ Whr$

On converting into Kwhr, we get

⇒ $=13.84 \ Kwhr$

6 0

3 years ago

A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What

nika2105 [10]

Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².

Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.

Given,

Radius of flywheel (r) = 1.96 cm = 0.0196m

Angular acceleration (α)= 13.0 rad/s²

The tangential acceleration formula is at=rα

where, α is the angular acceleration, and r is the radius of the circle.

using the formula; at=rα = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².

The tangential acceleration is 0.2548 m/s².

Learn more about the Tangential acceleration with the help of the following link:

brainly.com/question/15743294

#SPJ4

5 0

1 year ago

All electromagnetic waves travel in vacuum at the speed of c=3×10^8 m/s. Find the wavelength of microwaves of frequency 10^10 Hz

erica [24]

Recall the wave equation, $c=f\lambda$ where c is the speed of the wave (m/s), f is the frequency of the wave (Hz) and λ is the wavelength of the wave (m).

$c=f\lambda \Rightarrow \lambda = \frac{c}{f}$ so $\lambda = \frac{3 \times 10^8}{10^{10}} = 0.03 \text{m}$

5 0

3 years ago

10. How does surface area affect the amount of air resistance an object experiences?

ikadub [295]

Answer:cross-sectional area, and thus surface area, increases the amount of air resistance an object experiences

Explanation:

6 0

2 years ago

Two sound waves (speed 343 m/s) have different wavelengths. The first has a wavelength of 5.72 m, and the second a wavelength of

lys-0071 [83]

Answer:

The beat frequency is 30 Hz

Explanation:

Given;

velocity of the two sound waves, v = 343 m/s

wavelength of the first wave, λ₁ = 5.72 m

wavelength of the second wave, λ₂ = 11.44 m

The frequency of the first wave is calculated as follows;

F₁ = v/λ₁

F₁ = 343 / 5.72

F₁ = 59.97 HZ

The frequency of the second wave is calculated as follows;

F₂ = v/λ₂

F₂ = 343 / 11.44

F₂ = 29.98 Hz

The beat frequency is calculated as;

Fb = F₁ - F₂

Fb = 59.97 HZ - 29.98 Hz

Fb = 30 Hz

6 0

3 years ago