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3 years ago

Classify the measurement 80 blocks north.

Physics

1 answer:

Tasya [4]3 years ago

4 0

Answer:

Vector quantity

Explanation:

-A vector quantity refer to the physical quantity characterized by the presence of both magnitude as well as direction.

-The direction is given as North.

-The magnitude is given as 80 blocks.

#Hence, this is a vector quantity.

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An amusement park ride consists of a rotating circular platform 10.9 m in diameter from which 10 kg seats are suspended at the e

Darya [45]

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3 years ago

Underground water is being pumped into a pool whose cross section is 3 m x 4 m while water is discharged through a 0.076m-diamet

Svetllana [295]

Given:

Area of pool = 3m×4m
Diameter of orifice = 0.076m
Outlet Velocity = 6.3m/s
Accumulation velocity = 1.5cm/min

Required:

Inlet flowrate

Solution:

The problem can be solved by this general formula.

Accumulation = Inlet flowrate - Outlet flowrate
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

First, we need to convert the units of the accumulation velocity into m/s to be consistent.

Accumulation velocity = 1.5cm/min × (1min/60s)×(1m/100cm)
Accumulation velocity = 0.00025 m/s

We then calculate the area of the pool and the area of the orifice by:

Area of pool = 3 × 4 m²
Area of pool = 12m²

Area of orifice = πd²/4 = π(0.076m)²/4
Area of orifice = 0.00454m²

Since we have all we need, we plug in the values to the general equation earlier

Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

0.00025 m/s × 12m² = Inlet flowrate - 6.3m/s × 0.00454m²

Transposing terms,

Inlet flowrate = 0.316 m³/s

6 0

3 years ago

a charge of 7.2x10^-5C is placed in an Electric field with a strength of 4.8x10^5N/C. if the Electric potential energy of the ch

Alecsey [184]

Answer:

$d= 2.2 m$

Explanation:

The data given in the question is

Charge : q = $7.2 \times 10^{-5} C$

Electric field Strength : E = $4.8 \times 10^{5} N/C$

Electrical potential Energy : U = $75J$

Let, the distance be "d"

So, the formula for Electrical potential energy is

$U= q \times E \times d$

Simplified formula for distance become

$d=\frac{U}{q \times E}$

Now , insert the value

$d=\frac{75 J}{7.2 \times 10^{-5}C \times 4.8 \times 10^5 N/C}$

or,

$d=2.17 m$

Rounding off

$d= 2.2 m$

3 0

3 years ago

5. A bicyclist is finishing her repair of a flat tire when a friend rides by at a constant velocity of

FrozenT [24]

Answer:

a) t = 3.6 s

b) d = 23 m

c) v = 13 m/s

Explanation:

Let t be the time the accelerating rider rides

the distance she travels is

d = ½3.6t²

the distance for the other cyclist is

d =3.5(t + 3)

½3.6t² = 3.5(t + 3)

1.8t² - 3.5t - 10.5 = 0

quadratic formula, positive answer

t = (3.5 + √(3.5² - 4(1.8)(-10.5))) / (2(1.8))

t = 3.575786...

d = ½(3.6)(3.575786²) = 23.015...

v = 3.6(3.575786) = 12.8728...

8 0

2 years ago

7. A photon of violet light has a frequency of 7.57 x 10' Hz. How much

hichkok12 [17]

Answer:

3.13 eV

Explanation:

E = hf

f =7.57 x 10' Hz.

h = 6.62× 10-34Js

E = 6.62× 10-34 × 7.57 x 10' Hz

E = 5.011× 10^ -30 J

1eV = 1.6×10^-19J

Hence ,

5.011× 10^ -30 J ÷1.6×10^-19J

= 3.132×10^-49

8 0

3 years ago