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3241004551 [841]
2 years ago
13

Tommy runs around a track whose circumference is 400 meters. He runs a single lap in a time of 62 seconds. What is Tommy’s displ

acement
Physics
1 answer:
bija089 [108]2 years ago
8 0

Answer:

<h2>Angular Displacement 6.28 radians</h2>

Explanation:

for circular motion we are expected to solve for Angular Displacement it is measured in radian

Measurement of Angular Displacement.

we can measure it using the following relation

∅= s/r

where

s = the distance travelled by the body, and

r = radius of the circle along which it is moving.

given that

circumference c,  s= 400 m

r= ?

we have to solve for the radius

we know that circumference

c= 2\pi r

400= 2*3.142*r

400= 6.282*r

divide both sides by 6.284 we have

400/6.284

r= 63.63 m

Angular  displcament

∅= 400/63.63

∅= 6.28 radians

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An owl weighing 40N is sitting in a tree waiting to dive down to catch a mouse. If the owl's potential energy is 800 J with resp
Natali5045456 [20]

Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

The weight of an object of mass m is:

W = m.g

Thus, the GPE is:

U=W.h

Solving for h:

\displaystyle h=\frac{U}{W}

The weight of the owl is W=40 N and its GPE is U=800 J.

\displaystyle h=\frac{800}{40}=20

h = 20 m

3 0
3 years ago
A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the lens strength (a.k.a, lens p
Kipish [7]

Answer:

20.0 cm

Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

1/u = P'- 1/v

1/u = 55.0 D - 1/0.02 m

1/u = 55.0 m⁻¹ - 1/0.02 m

1/u = 55.0 m⁻¹ - 50.0 m⁻¹

1/u = 5.0 m⁻¹

u = 1/5.0 m⁻¹

u = 0.2 m

u = 20 cm

So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.

8 0
2 years ago
Current flows through a resistor; (a) with no direction since it is not a vector (b) from any potential to any different potenti
kykrilka [37]

Answer:

c)From high potential to low potential.

Explanation:

Given that

current is flowing through resister.

As we know that those quantity have direction as well as magnitude then these are called vector quantity and those quantity have only magnitude then they called scalar quantity.

As we know that current have direction as well as magnitude so current is a vector quantity.

Current flows from high potential to low potential.

8 0
3 years ago
Which sporting event is symbolic of American culture?
Zolol [24]
Baseball is known as americas past time
7 0
3 years ago
Read 2 more answers
Suppose the velocity of an object moving along a line is positive. are position, displacement, and distance traveled equal? expl
Pavlova-9 [17]

No, the object's displacement and distance travelled will be equal, but since the initial position is unknown, the object's position might not match up with its displacement and distance travelled.

We cannot assert that the displacement or distance equals the position because the initial position is not provided. We could reach a different conclusion if the starting position had been zero because the distance from zero is equal to the position.

Find more on velocity at : brainly.com/question/11347225

#SPJ4

4 0
2 years ago
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