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3241004551 [841]
3 years ago
13

Tommy runs around a track whose circumference is 400 meters. He runs a single lap in a time of 62 seconds. What is Tommy’s displ

acement
Physics
1 answer:
bija089 [108]3 years ago
8 0

Answer:

<h2>Angular Displacement 6.28 radians</h2>

Explanation:

for circular motion we are expected to solve for Angular Displacement it is measured in radian

Measurement of Angular Displacement.

we can measure it using the following relation

∅= s/r

where

s = the distance travelled by the body, and

r = radius of the circle along which it is moving.

given that

circumference c,  s= 400 m

r= ?

we have to solve for the radius

we know that circumference

c= 2\pi r

400= 2*3.142*r

400= 6.282*r

divide both sides by 6.284 we have

400/6.284

r= 63.63 m

Angular  displcament

∅= 400/63.63

∅= 6.28 radians

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Part A By what distance do two objects carrying 1.0 C of charge each have to be separated before the electric force exerted on e
aalyn [17]

Answer:

Part A: <em>4.74×10⁴ m</em>

P<em>art </em>B<em>: </em>0.000211 C

Explanation:

Part A:

From coulombs law,

F  = kq²/r²........................ Equation 1

Note: The two object are carrying equal charges.

Where F = Electric force, q = charge, r = distance of separation, k = proportionality constant

<em>Given: F = 4.0 N, q = 1.0 C, </em>

<em>Constant: k = 1/4πe₀ = 9×10⁹ Nm²/C²</em>

<em>Substituting these values into equation 1,</em>

<em>4 = 9×10⁹(1²)/r²</em>

<em>r² = (9×10⁹)/4</em>

<em>r² = 2.25×10⁹</em>

<em>r = √(2.25×10⁹)</em>

<em>r = 4.74×10⁴ m.</em>

<em>Part 2:</em>

<em>F = kq²/r²</em>

<em>Making q the subject of the equation</em>

<em>q = √(Fr²/k)........................... Equation 2</em>

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Substituting these values into equation 2

q = √(4×1²/(9×10⁹ )

q = 2.11/10⁴

q = 0.000211 C.

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