the answer to 3806 divided 22 is 173
Answer:
assuming you meant 6x198 do a mental sum for 6x200 (1200) then subtract 6x2(12)to give you 1188
Step-by-step explanation:
brainly.com/question/274291
Answer:
d= 8.6 ft
Step-by-step explanation:
In similar triangles, the corresponding sides are in proportion.

To find the value of x,

d = 8.6 ft
Answer:
x² + 2x + (3 / (x − 1))
Step-by-step explanation:
Start by setting up the division:
.........____________
x − 1 | x³ + x² − 2x + 3
Start with the first term, x³. Divided by x, that's x². So:
.........____x²______
x − 1 | x³ + x² − 2x + 3
Multiply x − 1 by x², subtract the result, and drop down the next term:
.........____x²______
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Repeat the process over again. First term is 2x². Divided by x is 2x. So:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Multiply, subtract the result, and drop down the next term:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
.................-(2x² − 2x)
.................---------------
.....................................3
x doesn't divide into 3, so that's the remainder.
Therefore, the answer is:
x² + 2x + (3 / (x − 1))
Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps